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Discussion of Problem 1012. K-based Numbers. Version 2

char array solution,i got 90 for 2 10,still wa #1
Posted by Yinthewind 6 May 2011 22:53
#include<stdio.h>
#include<stdio.h>

void plus(char *a,char *b,char *c)
{
    char *p1,*p2,*p3;
    p1=a+99;
    p2=b+99;
    p3=c+99;
    while(*p1!=0||*p2!=0)
    {
        *p3+=*p1+*p2-2*'0';
        if(*p3>'9')
        {
            *p3-=10;
            *(p3-1)+=1;
        }
        p1--;
        p2--;
        p3--;
    }
}
void multi(unsigned char *s,int k)
{
    unsigned char *p;
    p=s+99;
    while(*p!='0')
    {
        *p+=(*p-'0')*(k-1);
        p--;
    }
    p=s+99;
    while(*p!='0')
    {
        while(*p>'9')
        {
            *p-=10;
            *(p-1)+=1;
        }
        p--;
    }
}
void main()
{
    unsigned char a[101],b[101],c[101],d[101];
    int n,k,i,j;
    for(i=0;i<100;i++)
    {
        a[i]=b[i]=c[i]=d[i]='0';
    }
    scanf("%d %d",&n,&k);
    k-=1;
    a[100]='\0';
    b[100]='\0';
    c[100]='\0';
    a[99]=k+'0';
    b[99]=(k+k*k)%10+'0';
    b[98]=(k+k*k)/10+'0';
    for(i=1;i<n-1;i++)
    {
        strcpy(c,d);
        plus(a,b,c);
        multi(c,k);
        strcpy(a,b);
        strcpy(b,c);
    }

    i=0;
    while(*(b+i)=='0')
    {
        i++;
    }
    printf("%s",b+i);

}
Re: char array solution,i got 90 for 2 10,still wa #1
Posted by staticor 27 Jun 2013 23:38
no matter right or  wrong, bad code