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## Discussion of Problem 1044. Lucky Tickets. Easy!

help,please,why my solution fail?
Posted by mythysjh 2 Sep 2011 14:53
here is my code:

#include <stdio.h>
int total(int count, int sum)
{
int result = 0;
if( count > 1 )
{
int i=0;
for (; i <= 9; i++)
{
result += total(count - 1, sum     - i);
}
}
else
{
return  sum     < 10 && sum >= 0 ? 1 : 0;
}
return result;
}

int main ()
{
unsigned a;
int n,i,c,b;

scanf("%ud", &a);
b = a / 2 * 9;
for(i=0; i <= b; i++ )
{
c = total(a/2, i);
n += c * c;
}
printf("%d", n);

return 0;
}
i tried 2,4,6,8,the result is correct,but when i submit my solution,[wrong answer] is returned...

Edited by author 02.09.2011 14:58
Re: help,please,why my solution fail?
Posted by mythysjh 3 Sep 2011 06:58
i got it,in visual stdio 2010,auto variable must initialized before used
Re: help,please,why my solution fail?
Posted by Bahador Biglari 15 Dec 2011 12:18
Hello Smart :D,

Can you please explain how does your algorithm works? I find out that the summation of digits is multiplication of 9 at most; but why (c* c) ???? ( please explain the whole intention behind your algo as well.

Thanks
Re: help,please,why my solution fail?
Posted by killo 25 Jun 2012 16:20
Here is the correct code
#include <stdio.h>
int total(int count, int sum)
{
int result = 0;
if( count > 1 )
{
int i=0;
for (; i <= 9; i++)
{
result += total(count - 1, sum     - i);
}
}
else
{
return  sum     < 10 && sum >= 0 ? 1 : 0;
}
return result;
}

int main ()
{
unsigned a;
int n = 0;
int i,c,b;

scanf("%ud", &a);
b = a / 2 * 9;
for(i=0; i <= b; i++ )
{
c = total(a/2, i);
n += c * c;
}
printf("%d", n);

return 0;
}
Here is the correct code