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Discussion of Problem 2031. Overturned Numbers

No subject
Posted by Bahodir | TUIT of IT | 23 Jan 2015 23:49


Edited by author 27.01.2015 16:39
Re: wrong #4. is there any test ?. Help me... My code :
Posted by Bahodir | TUIT of IT | 27 Jan 2015 16:38
import java.util.Scanner;
/**
 * Created by Coder on 23.01.2015.
 */
public class OverturnedNumbers2031_ {
    public static void main(String[] args) {
        Scanner x = new Scanner(System.in);
        int n = x.nextInt();
        if (n == 1) {
            System.out.println("01");
        } else if (n == 2) {
            System.out.println("11 01");
        } else if (n == 4) {
            System.out.println("16 06 68 88");
        } else {
            System.out.println("Glupenky Pierre");
        }
    }
}
Re: wrong #4. is there any test ?. Help me... My code :
Posted by InstouT74 12 Feb 2015 23:16
You did not write a case of n=3..
Re: wrong #4. is there any test ?. Help me... My code :
Posted by Bahodir | IT of TUIT | 14 Feb 2015 22:18
Thanks a lot of.I got it. n = 3 -> "16 06 68";

Edited by author 14.02.2015 22:43
Re: wrong #4. is there any test ?. Help me... My code :
Posted by ImgJ 13 Apr 2015 22:52
The best solution ever xD
Re: No subject
Posted by Xayyam 14 Dec 2015 12:56
Why only 4 cases ??

Not all these are ok ??
"11", "01", "08", "06", "09", "10", "18", "16", "19", "80", "81", "86", "88", "89", "60", "68", "61", "66", "69", "90", "91", "98", "96", "99"