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| Show all threads Hide all threads Show all messages Hide all messages | | TO ADMINS!!!!!!!! | RAVEman | 1455. Freedom of Speech | 20 Oct 2022 08:30 | 5 | My program got WA8 all the time.
I have added next string to my program
if(n>50) vector<long> xxx(1000000);
and it got AC after that!!!
Variable "xxx" never uses in my code! If i delete this line it got WA8!!!! Please, send your program to my e-mail hi. I have sent you my program about an week ago. So what was the problem? Can you send your solution for me:)
I'll try to help
also I guarantee that I'll help with any of my solved problems
be shure I'll not cheat you;) Dear admin,
I'm also facing problem on WA-8. Although the guide page says that "the input data of this test case is not available, the solution author should find the cause of the error on their own", I have no idea on what error my program has. So I'm seeking for your help, can I contact you using email? | | test 24 | Heracle | 1455. Freedom of Speech | 14 Nov 2015 16:00 | 1 | Even if in the statement it is said that: "Albanian dictionary, found exactly N different words S[i] in it", in test 24 there are identical words, so be careful at this particular case. | | WA #6 | Baurzhan | 1455. Freedom of Speech | 18 Mar 2011 19:52 | 3 | WA #6 Baurzhan 19 Nov 2010 16:37 I implemented BFS solution and getting WA6. Persons,who ACed now but had problems with this test in the past,please,tell me,what is the possible reason of failure? For russian-speakers: i implemented approach, which K@DR explained me here: http://e-maxx.ru/forum/viewtopic.php?id=313 Edited by author 19.11.2010 16:40if you have WA6, try this test
2
ab
abab
answer:
YES
abab
But now I have problems with 8-th test:( Who can help me? if wa6, try this
4
ab
ba
aba
bab
YES
ababa
3
abcab
abc
c
YES
abcabc | | How to solve it? Need DP? | panyong0202 | 1455. Freedom of Speech | 3 Jul 2009 14:13 | 6 | There many ways:
1) hash
2) suffix array
3) suffix tree
4) suffix automation 10000 suffices,graph of they. Suffix s1 connected with
suffix s2 if exist word s, adjusting which to s1 we will have s2 as a rest. BFS in graph to find when rest will be equal empty:1) s=s1+s2; s=s3+s1+s4;s2=s1+s4.
Ac at last with above approach.
It imortant to right work with 20000.
Edited by author 22.11.2008 14:52 Create characters tree for all words (allowing direct per-character steps at O(1) and enumeration of all children also at O(1)). DP over IxJ, I - word number, J - suffix length. Cover these suffixes with other words till length delta become zero. I used Dijkstra for that because length can change arbitrarily. Start in words which contain some other word as a prefix.
Edited by author 20.08.2008 11:11 | | WA 12.(+) | Programmer | 1455. Freedom of Speech | 8 May 2009 23:37 | 1 | What is this test?
At first I had WA8. But then I change 20000->200000 and now WA 12. Who can help with this test? Thx. | | about test9 | Gunners | 1455. Freedom of Speech | 22 Nov 2008 14:46 | 3 | Can anyone tell me what's the trick of test9?
Thanks Just stack over flow, noting special.... Contrary to your I think that test 9 very hard
for it value 20000 is actual and I lost much bloode
fighting with it. | | Ambiguous statement | Vedernikoff Sergey (HSE: EconomicsForever!) | 1455. Freedom of Speech | 13 Jul 2008 23:06 | 2 | From the statement, words are not necessary different. So, am I right that for the input
2
ab
ab
output like
YES
ab
is right? found exactly N different words S[i] in it and realized | | TO ADMINS | panyong0202 | 1455. Freedom of Speech | 11 Aug 2007 08:54 | 1 | I think there are some bugs in my solution, but I got AC! | | About the length of the answer | Samsonov Alex [USU] | 1455. Freedom of Speech | 9 Apr 2007 19:46 | 2 | Is that true that if there is an answer, there is an answer shorter than 20001 symbol? Otherwise the statement is a bit strange. | | test 8 | RAVEman | 1455. Freedom of Speech | 6 Mar 2007 22:45 | 1 | test 8 RAVEman 6 Mar 2007 22:45 what is the 8th test? thanks! |
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