import sys

num = str(sys.stdin.readline().split()[0])
a = int(num[:3])
b = int(num[3:]) - 1
c = int(num[3:]) + 1
sum0 = sum([int(num) for num in str(a)])
sum1 = sum([int(num) for num in str(b)])
sum2 = sum([int(num) for num in str(c)])
if abs(sum0 - sum1 == 0) or abs(sum0 - sum2 == 0) or abs(sum1 - sum0 == 0) or abs(sum2 - sum0 == 0):
    print("Yes")
else:
    print("No")

a = input()
row = []
for i in a:
    row.append(i)
for i in range(len(row)):
    row[i] = int(row[i])
suml = row[0] * 100 + row[1] * 10 + row[2]
sumr = row[3] * 100 + row[4] * 10 + row[5]
if suml - sumr == 1 or sumr - suml == 1:
    print('yes')
else: print('no')

a = input()
minussum=0
plussum=0
b =[0:3]
c =[3:6]
c=int(c)
minus = c-1
plus = c+1
minus=str(minus)
plus=str(plus)
for i in minus:
    i=int(i)
    minussum+=i
for i in plus:
    i=int(i)
    plussum+=i
n=0
for i in b:
    i=int(i)
    n+=i
if n == minussum or n == plussum:
    print("Yes")
else:
    print("No")




Help please)
Why re?

Edited by author 13.09.2022 23:21

import java.util.*;
public class LuckyNumber{
 public static void main(String args[]){
Scanner in = new Scanner(System.in);
int x = in.nextInt();
 int a1,a2,a3,b1,b2,b3;
a1 = x/100000; a2 = (x/10000)%10; a3 = (x/1000)%10;
b1 = (x/100)%10; b2 = (x/10)%10; b3 = x%10;
     if((a1+a2+a3) == (b1+b2+b3)) System.out.println("Lucky Number");
 else if(a1+a2+a3-(b1+b2+b3)>1 ||(b1+b2+b3)-(a1+a2+a3)>1) {
     System.out.println("prostoi bilet");
 }
else System.out.println("Lucky Number budet sleduwii ili prediduwi bilet");
     }
        }

#include<iostream>

using namespace std;
int sum(int temp);
int main(){
    int a[6];
    scanf("%1d%1d%1d%1d%1d%1d",&a[0],&a[1],&a[2],&a[3],&a[4],&a[5]);
    int first=a[0]*100+a[1]*10+a[2];
    int second=a[3]*100+a[4]*10+a[5];
    if(a[3]==9&&a[4]==9&&a[5]==9){
        cout<<"No";
        return 0;
    }
    int pre=second-1;
    int next=second+1;
    if((sum(pre)==(a[0]+a[1]+a[2]))||(sum(next)==(a[0]+a[1]+a[2]))){
        cout<<"Yes";
    }else{
        cout<<"No";
    }

return 0;
}

int sum(int temp){
    int count=0;
    do{
        count+=(temp%10);
        temp/=10;
    }while(temp/10!=0);
    count+=temp;
    return count;
}

Am I stupid or what?
code seems to be working

var x,a,b:integer;
function sum(x:integer): INTEGER;
  var s:integer;
  begin
  while x>0 do
    begin
    s:=s+x mod 10;
    x:=x div 10;
    end;
  sum:=s;
  end;
begin
read (x);
a:=x div 1000;
b:=x mod 1000;
if (sum(a)=sum(b+1)) or (sum(a)=sum(b-1)) then writeln ('Yes')
else writeln ('No');
end.

Проверяйте пограничные ситуации, когда номер билета на входе 000000 или 999999

New tests have been added. 86 authors have lost their AC.

вообще не могу понять что не так. проходят пробные тесты,проходят тесты которые нашла в обсуждениях.
если не трудно может покидаете тесты, плииз...

var a,a1,a2,s1,s,ap,al,sm1p,sm2p,sm3p,smap,sm1l,sm2l,sm3l,smal,s2,s3:Integer;
begin
ReadLn(a);
a1:=a+1;
a2:=a-1;

ap:=a1 div 1000;
al:=a1 mod 1000;

sm1p:=ap div 100;
sm2p:=ap mod 100 div 10;
sm3p:=ap mod 10;
smap:=sm1p+sm2p+sm3p;

sm1l:=al div 100;
sm2l:=al mod 100 div 10;
sm3l:=al mod 10;
smal:=sm1l+sm2l+sm3l;

if smal=smap then Writeln('YES')
     else
     begin
     ap:=a2 div 1000;
     al:=a2 mod 1000;

     sm1p:=ap div 100;
     sm2p:=ap mod 100 div 10;
     sm3p:=ap mod 10;
     smap:=sm1p+sm2p+sm3p;

     sm1l:=al div 100;
     sm2l:=al mod 100 div 10;
     sm3l:=al mod 10;
     smal:=sm1l+sm2l+sm3l;
     if smal=smap then Writeln('YES')
             else
                  WriteLn('NO');
     end;
end.

I think my code is right but it is not getting accepted. Can anyone help me figure out what is wrong ?

The python code is as follows:

n=input()
sum1=0
sum2=0
for i in range(0,3):
    sum1=sum1+(int(n[i]))
for i in range(3,6):
    sum2=sum2+(int(n[i]))
if(1==(abs(sum1-sum2)) or 0==sum1-sum2):
    print("Yes")
else:
    print("No")


Pls help me solve the issue

Edited by author 23.11.2017 13:45

#include<iostream>
using namespace std;

int main()
{
    int x, y;
    int sum1 = 0, sum2 = 0;
    char n = 'n';

    cin >> x;
    int max = x + 1;
    int min = x - 1;
    for (int i = 0; i <3; i++)
    {
        y = max % 10;

        max = max / 10;
        sum1 += y;
    }
    for (int i = 0; i < 3; i++)
    {
        y = max % 10;

        max = max / 10;
        sum2 += y;

    }
    if (sum2 == sum1)
    {
        n = 'y';

    }

    y = 0;
    sum1 = 0;
    sum2 = 0;
    for (int i = 0; i <3; i++)
    {
        y = min % 10;

        min = min / 10;
        sum1 += y;
    }
    for (int i = 0; i <3; i++)
    {
        y = min % 10;

        min = min / 10;
        sum2 += y;
    }
    if (sum2 == sum1)
    {
        n = 'y';

    }
    if (n=='n')
    {
        cout << "no";
    }
    else
    {
        cout << "yes";
    }
    return 0;
}

#include <iostream>
long int a,b,c,d,e,f,n,z,x,a1,a2;
using namespace std;
void main() {
    cin >>a;
    n=a%10;
    f=a%100;
    f=f/10;
    e=a%1000;
    e=e/100;
    d=a%10000;
    d=d/1000;
    c=a%100000;
    c=c/10000;
    b=a%1000000;
    b=b/100000;
    if ((n==9)||(f==9)||(e==9)) {
        z=(e+f+n)+1%10;
    } else {
        z=e+f+n;
    } if ((d==9)||(c==9)) {
        x=(b+c+d)+1%10;
    } else {
        x=b+c+d;
    }
    a1=z-x;
    a2=x-z;
    if ((a1==1)||(a2==1)) {
        cout <<"Yes";
    } else {
        cout <<"No";
    }
}

my code:

#include <stdio.h>
#include <math.h>
#include <string.h>
#include <conio.h>
int SL (int n)
{
  int q=n/1000, i, s=0;
  while (q>10)
  {
    s+=q%10;
    q/=10;
  }
  s+=q;
  return s;
}
int SR (int n)
{
  int s=0,q=n%1000;
  while (q>10)
  {
    s+=q%10;
    q/=10;
  }
  s+=q;
  return s;
}
void main()
{
  int S=0,T=0,N;
  scanf ("%d", &N);
  if ((SR(N+1)==SL(N+1))||(SR(N-1)==SL(N-1)))
    printf ("Yes");
  else printf ("No");
}

I got AC on VB .NET 2010 !!!
Write me on mail saucy_smile@mail.ru and I'll send you the source code :-)

Edited by author 24.08.2016 08:07

Edited by author 24.08.2016 08:08

//Timus1493

#include <iostream>
using namespace std;

//Creates a copy and does not change the argument
int sum_of_3(int num)
{
    int result = 0;

    for (int i = 1; i <= 3; i++)
    {
        result += num % 10;
        num /= 10;
    }
    return result;
}

int main ()
{
    int num;
    cin >> num;

    int digit = num % 10, right = sum_of_3(num), left = sum_of_3(num / 1000);



    if ((left > right  && digit == 9) || (left < right  && digit == 0))
        cout << "No \n";
    else
        cout << "Yes \n";

    cout << num;

    return 0;


}

445219- No
4+4+5 = 13
2+1+9 = 12
13 and 12 = 1
Yes?
Why not?

In a different IDE with all boundary conditions checked, it's working but it shows run-time error at test #8, not sure why.

import sys
def compute_sum(n):
    return int(n[0]) + int(n[1]) + int(n[2]) - int(n[3]) - int(n[4]) - int(n[5])

n = input()
s2 = 1
s3 = 1
if int(n) == 0 or int(n) == 999999:
    print ('Yes')
    sys.exit()
s1 = compute_sum(n)

if len(str(int(n))) < 6:
    d = 6 - len(str(int(n)))
    s2 = compute_sum('0' * d + str(int(n) - 1))
    s3 = compute_sum('0' * d + str(int(n) + 1))
else:
    s2 = compute_sum(str(int(n) - 1))
    if len(str(int(n) + 1)) <= 6:
        s3 = compute_sum(str(int(n) + 1))

if abs(s2) == 0 or abs(s3) == 0:
    print ("Yes")
else:
    print ("No")

I disagree with the result in example 2 to the task 1493. According to the problem, must output "Yes", because 445219 in the summation of the digits gives 13 and 12. These numbers differ by 1. The example says "No". When checking the solution 2, the test system writes "Wrong answer". Please fix the problem or explain me the condition.

this is my solution
#include <iostream>
#include <cmath>
using namespace std;

int main()
{
   long long a,b,s=0,d=0,k=0,jama,kk=0,ss=0,dd=0;
   cin>>b;
   a=b;
   b=b-1;
   while(b-1>0)
   { jama=b%10;
       k++;
       if(k<=3)
       {
           s+=jama;
       }
       else{
        d+=jama;
       }
       b/=10;

   }

   int i=0;
   if(s-d==0 )
   {
      i++;

   }

   a=a+1;
   int joma;
    while(a>0)
   { joma=a%10;
       kk++;
       if(kk<=3)
       {
           ss+=joma;
       }
       else{
        dd+=joma;
       }
       a/=10;

   }
   if(ss-dd==0 )
   {
      i++;

   }
   if(i>0)
   {
       cout<< "Yes";

   }
   else
    cout<< "No";
    return 0;
}

include <iostream>
using namespace std;
int main()
{

    int N=0,a=0,b=0;
    cin>>N;
    a=(N/100000)+(N/10000-N/100000*10)+(N/1000-N/10000*10);
    b=(N/100-N/1000*10)+(N/10-N/100*10)+(N-N/10*10);
    if(a-1==b){
        cout << "YES\n";
    } else {
        cout << "NO\n";
    }
    return 0;
}