pair <int,int> rotate(int x,int y) {
    return make_pair(y,3-x);
}

 #include <iostream>
using namespace std;

char paper[4][4], pass[4][4],rPass[16],TempPaper[4][4];
int v, i, j;

void check(char paper[4][4], char pass[4][4])
{
    for (int j = 0; j < 4; j++)// X/.
    {
        for (int i = 0; i < 4; i++)
        {
            if (paper[j][i] == 'X')
            {
                rPass[v] = pass[j][i];
                v++;
            }

        }
    }
}

int main()
{
    for (int j = 0; j < 4; j++) //paper cin
    {
        for (int i = 0; i < 4; i++)
        {
            cin >> paper[j][i];
        }
    }

    for (int j = 0; j < 4; j++)//зашифрованый пароль
    {
        for (int i = 0; i < 4; i++)
        {
            cin >> pass[j][i];
        }
    }
    for (int j = 0; j < 4; j++)//temp
    {
        for (int i = 0; i < 4; i++)
        {
            TempPaper[j][i] = paper[j][i];
        }
    }
    check(paper, pass);
    for (i = 0; i < 4; i++)
    {
        for (j = 0; j < 4; j++)
        {
            int t=0, y;
            if (j == 0)
            {
                int u = 3;
                for (y = 0; y < 4; y++)
                {
                    paper[t][u] = TempPaper[0][y];
                    t++;
                }
            }
            if (j == 1)
            {
                int u = 2;
                for (y = 0; y < 4; y++)
                {
                    paper[t][u] = TempPaper[1][y];
                    t++;
                }
            }
            if (j == 2)
            {
                int u = 1;
                for (y = 0; y < 4; y++)
                {
                    paper[t][u] = TempPaper[2][y];
                    t++;
                }
            }
            if (j == 3)
            {
                int u = 0;
                for (y = 0; y < 4; y++)
                {
                    paper[t][u] = TempPaper[3][y];
                    t++;
                }
            }
        }
        check(paper, pass);
        for (int j = 0; j < 4; j++)
        {
            for (int i = 0; i < 4; i++)
            {
                TempPaper[j][i] = paper[j][i];
            }
        }
        }
    return 0;
}

Can anybody explain me why one program can have different execution time with the same code?
My friend with my code got 0.015 but I got 0.031.

Oops =)
I send it one more time and get 0.015.
Maybe it because of server...

Edited by author 22.11.2010 21:59

My AC solution outputs extra empty line before outputing answer for the task. I think, it is not right, or I'm mistaken?

wy wrong#2 help me please!!! What is second test

here my program, prompt in what a mistake. when I send to check the error of compilation writes...
#include <iostream>
using namespace std;

void main() {
const int n = 4;
char Resh[n][n], OldResh[n][n], Shifr[n][n];

for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
cin » Resh[i][j];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
cin » Shifr[i][j];

for (int k = 0; k < 4; k++) {
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
if (Resh[i][j] == 'X') cout « Shifr[i][j];

for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
OldResh[i][j] = Resh[i][j];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
Resh[i][j] = OldResh[n - 1 - j][i];
}

system("pause");
}

Edited by author 24.05.2013 01:05

Code in C#!!!
first of ALL just print and reverse print .... 3 times

     static string [,] reverse(string[,] arr)
        {
            string[,] tmp = new string [4,4];

            for (int i = 0; i < 4; i++)
            {
                for (int j = 0; j < 4 ; j++)
                {
                    tmp[i,j] = arr[4-j-1,i];
                }
            }
            return tmp;
        }
in this case i wrote code for 4x4 array!!!
you can change your code to tmp[i,j] = arr[3-j,i]
if u want reverse nxn array change all 4 to n
GooD Luck!
sorry for my english!!

Edited by author 17.10.2012 02:39

program Project3;

{$APPTYPE CONSOLE}

uses
  SysUtils;

type
  re=array[1..4,1..4] of char;
  var
  c,r:re ;

  i,j:integer;
  s:string;

   procedure vyvod(m:re) ;
  begin
   for I := 1 to 4 do
for j := 1 to 4 do
if m[i,j]='X' then write(r[i,j]);
  end;

  procedure perevorot(var w:re) ;
  var
  w2:re;
  begin
  vyvod(w);
  for I := 1 to 4 do
  for j := 1 to 4 do
  w2[i,j]:='.';
    for I := 1 to 4 do
      if w[1,i]='X' then   w2[i,4]:='X';
     for I := 1 to 4 do
      if w[4,i]='X' then   w2[i,1]:='X';
      for I := 2 to 3 do
        if w[i,1]='X' then  w2[1,5-i]:='X';
         for I := 2 to 3 do
        if w[i,4]='X' then  w2[4,i]:='X';
        //rgrgr    X
        if w[2,2]='X' then  w2[2,3]:='X';
        if w[2,3]='X' then  w2[3,3]:='X';
        if w[3,3]='X' then  w2[3,2]:='X';
        if w[3,2]='X' then  w2[2,2]:='X';
        for I := 1 to 4 do
       for j := 1 to 4 do
       w[i,j]:=w2[i,j];



  end;


begin
for I := 1 to 4 do      begin
for j := 1 to 3 do           begin
read(c[i,j]);
end;
readln(c[i,j]);
end;
 for I := 1 to 4 do    begin
for j := 1 to 3 do          begin
read(r[i,j]);
end;
  readln(r[i,j]);
 end;
perevorot(c);
perevorot(c);
perevorot(c);
perevorot(c);
readln;readln;

end.

Please give me test 5# if you have,or send me your code (oa1990_10_17@mail.ru).
#include"iostream"
using namespace std;
void Tar(int K[][2]);
int main()
{
    int K[4][2],k=0;
    char s[4][5],c,ss[17];
    for(int i=1;i<=4;i++)
        for(int j=1;j<=4;j++)
        {
            cin>>c;
            if(c=='X')
            {
                K[k][0]=i;
                K[k][1]=j;
                k++;
            }
        }
        for(int i=0;i<4;i++)
        {
            cin>>s[i];
        }
        k=0;
        for(int i=1;i<5;i++)
        {
            ss[k]=s[K[0][0]-1][K[0][1]-1];
            k++;
            ss[k]=s[K[1][0]-1][K[1][1]-1];
            k++;
            ss[k]=s[K[2][0]-1][K[2][1]-1];
            k++;
            ss[k]=s[K[3][0]-1][K[3][1]-1];
            k++;
            for(int j=0;j<4;j++)
            {
                int t=K[j][0];
                K[j][0]=K[j][1];
                K[j][1]=5-t;
            }
            Tar(K);
        }
        ss[16]='\0';
        cout<<ss;
    return 0;
}
void Tar(int K[][2])
{
    for(int i=0;i<4;i++)
    {
        for(int j=i+1;j<4;j++)
        {
            if(K[j][0]<K[i][0])
            {
             int k=K[i][0],t=K[i][1];
             K[i][0]=K[j][0];
             K[i][1]=K[j][1];
             K[j][0]=k;K[j][1]=t;
            }
        }
    }
    for(int i=1;i<4;i++)
    {
        if(K[i][0]==K[i-1][0]&&K[i][1]<K[i-1][1])
        {
            int t=K[i][1];
            K[i][1]=K[i-1][1];
            K[i-1][1]=t;
        }
    }
}

1.find out the equtaion, to get next location of new character after rotation each time.
2.sort the locations on basis of height.
3. print the characters on those locations.

All the best.

Regards
Anupam

Edited by author 06.11.2011 04:53

my solution

#include<string>
#include<iostream>
using namespace std;
int main()
{char a[4][4],c[4][4];
int  b[4][4],i,j,t;


for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
cin>>c[i][j];
for(i=1;i<=4;i++)
for(j=1;j<=4;j++)

cin>>a[i][j];
cout<<endl;
//1 qator
for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='X')
cout<<a[i][j];
//2-qator
for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='X')
  c[j][5-i]='1';


  for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='1')
cout<<a[i][j];

//3-qator

for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='1')
c[j][5-i]='2';

for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='2')
cout<<a[i][j];

for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='2')
c[j][5-i]='3';
for(i=1;i<=4;i++)
for(j=1;j<=4;j++)
if(c[i][j]=='3')
cout<<a[i][j];
}

in 1712 i have made this:
[code deleted]
 why is a wrong answer????

Edited by moderator 19.11.2019 22:45

I AM SO SCARED OF THIS PROBLEM, AAAAAH

my e-mail is griszka90@wp.pl

why WA in test 7 ????

i need it

ofcourse i've tried it on my computer
it runs that program just fine
i've tried submitting my solution
3 times. why is it giving me CE and WA

can anyone explain it?

leks130992@mail.ru