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Discussion of Problem 1021. Sacrament of the Sum

Pomogite TLE na 10 teste ; Help TLE on 10 th test
Posted by Hamdam_TUIT 28 Jun 2013 10:37
#include<iostream>
using namespace std;

short a[50001],b[50001];
int N,M,index_1_0,index_1_10,index_2_0,index_2_10;
bool f_0,f_10,t_0,t_10;
const int T=10000;

int main()
{
    cin>>N;
    for(int i=0;i<N;i++)
    {
        cin>>a[i];
        if(a[i]>=0&&!f_0)
        {
            index_1_0=i;
            f_0=true;
        }
        if(a[i]>=1000&&!f_10)
        {
            index_1_10=i;
            f_10=true;
        }
    }
    cin>>M;
    for(int i=0;i<M;i++)
    {
        cin>>b[i];
        if(b[i]<=0&&!t_0)
        {
            index_2_0=i;
            t_0=true;
        }
        if(b[i]<=1000&&!t_10)
        {
            index_2_10=i;
            f_10=true;
        }
    }
    for(int i=0;i<=index_1_0;i++)
    {
        for(int j=0;j<=index_2_10;j++)
        {
            if(a[i]+b[j]<1000)
            break;
            if(a[i]+b[j]==T)
            {
                cout<<"YES";
                return 0;
            }
        }
    }
    for(int i=index_1_0;i<=index_1_10;i++)
    {
        for(int j=index_2_10;j<=index_2_0;j++)
        {
            if(a[i]+b[j]<1000)
            break;
            if(a[i]+b[j]==T)
            {
                cout<<"YES";
                return 0;
            }
        }
    }
    for(int i=index_1_10;i<N;i++)
    {
        for(int j=index_2_0;j<M;j++)
        {
            if(a[i]+b[j]<1000)
            break;
            if(a[i]+b[j]==T)
            {
                cout<<"YES";
                return 0;
            }
        }
    }
    cout<<"NO";
    }

Edited by author 28.06.2013 11:46