please help me !!!!!!!!
I  submissions  14 time
this is my code
#include<stdio.h>
int main()
{   char str0[100];
    int str1[100],str2[100],str3[100];
    int i,len=0;
     gets(str0);
      for(i=0;str0[i]!='\0';i++,len++)  str1[i]=str0[i]-'a';

       str2[0]=str1[0];
       for(i=1;i<len;i++)
       {  str2[i]=str1[i];
         while(str2[i]<str2[i-1])
        {   str2[i]+=26;

         }
       }

        str3[0]=str2[0]-5;
        for(i=0;i<len;i++)
        str3[i+1]=str2[i+1]-str2[i];

       for(i=0;i<len;i++)
         printf("%c",(str3[i]%26)+'a');


}

Edited by author 28.11.2006 22:06

Edited by author 28.11.2006 22:08

not (a[0] in ['a'..'z'])!!

What I wanna tell you is that this problem is really easy to solve. You only need to have a really good thinking. Try to find the changes between each letters or numbers. Then you'll work it out!

The problem is that you haven't considered the case where str[0]<'a'+5. In this case when you do str[0]-=5 at the end a value lesser than 'a' may be obtained. Hence  at the end if (str[0]-=5)<0 then str[0]+=26.

Try this test case once
bimdhhycaoinese

Answer should be
whereareyoufrom

you get [hereareyoufrom if you havent taken care of the condition.

<<jagatsastry>>

A lot of Thanks))

Thanks!

<jagatsastry>
Thank you very much for explanation

<jagatsastry>
Thank you very much for explanation