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вернуться в форумvar i,k:longint; begin read(k); i:=k div 3; while(k mod i<>0) do i:=k div(k div i +1); write(k div i-1); end. Edited by author 19.05.2007 23:58 So fabulous. Excellent... After you found maximal divider of K you can found minimal devider of K.... Excellent solution... Explain this solution, please. I'm a beginning programmer, so I can't understand. |
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