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back to board#include<stdio.h>
#include<math.h>
int main()
{
int n;
printf("%d\n",scanf("%d",&n)*n*scanf("%d",&n)*n*scanf("%d",&n)*n*2);
} you write so complex, the answer is N*A*B*2 why so complex man!! Should it work at all? Isn't it unspecified behavior - n is modified 3 times in the same expression? Brother, you should solve it step by step!Don't do all things in printf function.In this way u can easily find you bug! You can follow this method n*a*b*2 |
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