Discussion @ 2011. Long Statement @ Timus Online Judge

Sherxon WIUT No Need To Use Loop, Only If can solve it [9] // Problem 2011. Long Statement 27 Nov 2014 01:14

Bakhodir Boydedaev Re: No Need To Use Loop, Only If can solve it // Problem 2011. Long Statement 6 Dec 2014 19:28

...

Edited by author 06.12.2014 19:30

Habib Re: No Need To Use Loop, Only If can solve it [7] // Problem 2011. Long Statement 9 Aug 2017 09:40

I solve without loop but is return WA#4

There is my algorithm :
if in list has 1 , 2 , 3 together always "Yes"
otherwise "No" am I right or any case is there ?

Edited by author 09.08.2017 09:41

Edited by author 09.08.2017 09:42

Nikita Mogilevets Re: No Need To Use Loop, Only If can solve it [6] // Problem 2011. Long Statement 12 Aug 2017 16:24

You can get six combinations with two a's and two b's

You can get six combinations with one a and five b's

Habib Re: No Need To Use Loop, Only If can solve it [5] // Problem 2011. Long Statement 16 Aug 2017 15:45

Sorry but I don't understand what do you mean !
Give me Test Case #4

Nikita Mogilevets Re: No Need To Use Loop, Only If can solve it [4] // Problem 2011. Long Statement 17 Aug 2017 00:16

0011
0101
0110
1001
1010
1100

That is six

Nikita Mogilevets Re: No Need To Use Loop, Only If can solve it [1] // Problem 2011. Long Statement 17 Aug 2017 00:17

000001
000010
000100
001000
010000
100000

That is also six

Nikita Mogilevets Re: No Need To Use Loop, Only If can solve it // Problem 2011. Long Statement 17 Aug 2017 00:17

012
021
102
120
201
210

And that is six

Habib Re: No Need To Use Loop, Only If can solve it [1] // Problem 2011. Long Statement 30 Aug 2017 11:22

Answer is No , Correct ?

Nikita Mogilevets wrote 17 August 2017 00:16

0011
0101
0110
1001
1010
1100

That is six

Nikita Mogilevets Re: No Need To Use Loop, Only If can solve it // Problem 2011. Long Statement 30 Aug 2017 18:43

https://ideone.com/hG0aZ4
I do not want to say anything more
Maybe just look at my code

Discussion of Problem 2011. Long Statement