#include<stdio.h>
#include<math.h>
double str[300000];
using namespace std;
int main()
{
    double a;
    int w=0;
    while(~scanf("%lf",&str[w]))
        w++;
    for(int i=w-1;i>=0;i--)
        printf("%.6f\n",sqrt(str[i]));
    return 0;
}
//Don't use cin or cout
//str[N],Nshould>=262144