|
|
back to boardShow all messages Hide all messages int main(){
long long a;
double b=0;
int count=0;
double *array = (double *)malloc(sizeof(double));
while(scanf("%lld",&a)){
b = sqrt(a);
array[count]=b;
count++;
}
for(int i = count-1; i >= 0; i--){
printf("%f\n",array[i]);
}
return 0;
}
my code is showing above, but each time it returns the runtime error. i run it on my PC but everything is fine. is there any runtime error here?
thanks! There is access violation
Your array is only ONE element in size
It works on your PC because your runtime environment does not checks whether you are violating borders of memory
Memory allocation is just a promise to use allocated memory
But in C++, there are no checks by default
So it is programmer's task to ensure there is no BUFFER OVERRUN. So malloc(sizeof(double) *N)
returns memory for N doubles
In your case N is just one When you allocate memory
System is not permitted to use that memory for it's operations
Because if it uses
You may change system parameters and break down the system |
|
|
