ENG  RUS Timus Online Judge
Online Judge
Problems
Authors
Online contests
Site news
Webboard
Problem set
Submit solution
Judge status
Guide
Register
Authors ranklist
Current contest
Scheduled contests
Past contests
Rules
back to board

## Discussion of Problem 2000. Grand Theft Array V

accepted
Posted by Mikhail 16 May 2018 00:41
//#pragma GCC optimize("Ofast,no-stack-protector")
//#pragma GCC target("avx")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;
using namespace std;

#define re return
#define pb push_back
#define eb emplace_back
#define all(x) (x).begin(), (x).end()
#define fi first
#define se second
#define sqrt(x) sqrt(abs(x))
#define mp make_pair
#define pi (3.14159265358979323846264338327950288419716939937510)
#define fo(i, n) for(int i = 0; i < n; ++i)
#define ro(i, n) for(int i = n - 1; i >= 0; --i)
#define unique(v) v.resize(unique(all(v)) - v.begin())

template <class T> T abs (T x) { re x > 0 ? x : -x; }
template <class T> T sqr (T x) { re x * x; }
template <class T> T gcd (T a, T b) { re a ? gcd (b % a, a) : b; }
template <class T> int sgn (T x) { re x > 0 ? 1 : (x < 0 ? -1 : 0); }

typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<string> vs;
typedef double D;
typedef long double ld;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef unsigned long long ull;
typedef tree <pair<int, char>, null_type, less<pair<int, char>>, rb_tree_tag, tree_order_statistics_node_update> _tree;

const int maxn = (int) 1e5;
int a[maxn];

int main() {
int n;
scanf("%d", &n);
fo(i, n) scanf("%d", a + i);
int p1, p2;
scanf("%d%d", &p1, &p2);
--p1, --p2;
if (p1 == p2) {
int sum1 = 0, sum2 = 0;
fo(i, p1) sum1 += a[i];
for (int j = p1 + 1; j < n; ++j) sum2 += a[j];
cout << max(sum1, sum2) + a[p1] << ' '<< min(sum1, sum2) << endl;
re 0;
}
bool _swap = p1 > p2;
if (p1 > p2) swap(p1, p2);
int middle = p1 + (p2 - p1 - 1) / 2 + (((p2 - p1 - 1) & 1) && !_swap);
ll sum1 = 0, sum2 = 0;
fo(i, n) {
if (i <= middle) sum1 += a[i];
else sum2 += a[i];
}
if (_swap) swap(sum1, sum2);
cout << sum1 << ' '<< sum2 << endl;
}