a, b = map(int, input().split())
print(10-a, 10-b)

whats wrong with this logic?
cout<<10-a<<" "<<10-b<<endl;

#include<iostream>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    cout << b-1 << ' ' << a - 1;
}

#include<stdio.h>

int main() {
   int  h, l;
   scanf("%d %d", &h, &l);
   int total = h + l;
   printf("%d %d\n", total - l - 1, total - h - 1);
   return 0;
}

#include <stdio.h>
#include <stdlib.h>
int main(){
    int harry,larry,res,res1,c;
    scanf("%d %d",&harry,&larry);
    c=(harry+larry)-1;
    if(c<=10){
        res1=10-harry;
        res=10-larry;
        printf("%d %d \n", res1,res);


    }else


    return 0;

}

Got this by first try, I didn't opened IDE, didnt'y opened even notepad. I wrote it right in the input box. Too easy.

why wrong answer?


#include"iostream"

int main()
{

         int banki=10;
    int Garry,Larry;
    std::cin>>Garry>>Larry;
    std::cout<<banki-Garry<<" "<<banki-Larry;
    return 0;
}

#include<iostream>

using namespace std;
int main()
{
int a;
int b;

int c;
int d;
int h;
cin>>a;
cin>>b;
h=a-1+b;
c=h-a;
d=h-b;
cout<<c;
cout<<d;

return 0;
}

Seems an easy problem, but I can't understand it...

I don't understand what's wrong with my code. Help me pls. Thnx in advance.

#include<stdio.h>

int main(){
    int L, H;
    scanf("%d%d", &L, &H);
    printf("%d %d ", 10 - L, 10 - H);

    return 0;
}

[code deleted]

===
Return "Fail (checker)", why?

Edited by moderator 20.11.2019 00:01

KTO NIBUD PONIMAET, KAK EE RESHIT

[code deleted]

Edited by moderator 19.11.2019 23:54

What is wrong in my code? Thanks

[code deleted]

Edited by moderator 19.11.2019 23:57

why wrong answer?? help please.
var a,b,c,d:integer;
begin
readln(a,b);
c:=10-a;
d:=10-d;
writeln(c);
writeln(d);
end.

Dear All,

I am a student and I got an assignment from my teacher to run "1409 Two Gangsters". I write Python program v.2.7 as per following codes. I run the program many times, but it still showed "Runtime Error". I could not fix it.

It would be appreciated if someone can help me. Thanks.


# 1409 Two Gangsters (Created: 24th June 2015 / Python 2.7)


# -------------------- Start of Program -------------------- #

# Set initial values
total = 0    # total number of cans shot by Harry and Larry
Harry = 0    # the number of cans shot by Harry
Larry = 0    # the number of cans shot by Larry
h = 0            # the number of cans that were not shot by Harry
l = 0           # the number of cans that were not shot by Larry


Harry = int(input("Please enter the number of cans shot by Harry: ")
Larry = int(input("Please enter the number of cans shot by Larry: ")


# Calculation of "The number of cans that were not shot by Harry and Larry"
total = Harry + Larry -1
h = total - Harry
l = total - Larry


# Output
print "-"*100
print "Total number of cans are : ", total
print "The number of cans that were not shot by Harry and Larry are ", h, "and", l, "respectively."
print "-"*100




# -------------------- End of Program -------------------- #

#include<stdio.h>

void main()
{
    int harry, larry;
    int sum;
    int harryleft, larryleft;

    scanf("%d%d", harry, larry);
    sum = (harry + larry)-1;
    harryleft = sum - harry;
    larryleft = sum - larry;
    printf("%d%d", harryleft, larryleft);

        return 0;
}

why wrong answer?
#include <iostream>
using namespace std;
int main()
{
    int banki=10, banki_s, bankis_ss;
    cout << "Harry shot cans: ";
    cin >> banki_s;
    cout << "Larry shot cans: ";
    cin >> bankis_ss;
cout << "Harry shot: " << (banki - banki_s) << endl;
cout << "Larry shot: " << (banki - bankis_ss) << endl;

    return 0;
}

why output b-1 and a-1 you will get an AC?
because there's always one common can
in this way there are a+b-1 cans in total
then Larry has a+b-1-a=b-1 cans left
so does Harry

the statement is very unclear....