just the rule of multiplication in combinatorics...

Can somebody give me the whole explanation to this problem. Thanks beforehand!

  if(s.equals("Blue")|| s.equals("blue"))
  if(s.equals("Red") || s.equals("red"))
  if(s.equals("Yellow") || s.equals("yellow"))

what is test 5?

Very easy just write c(b,b1)*c(r,r1)*c(y,y1). Where  b1 ,r1,y1 is the number of red, blue,yellow colors. note function c isn't in library you should write it .
For more about C read here  http://en.wikipedia.org/wiki/Binomial_coefficient

Can Smb Explain The Prob. Or The Sample Output

I got AC, but while looking at your solutions, i have guessed following:

Nobody paid attention, that here may be more, than 3 potions: Total number of types of any potion is equal to 15:

B, R, Y;

B + R = V (Violet)
B + Y = G (Green)
R + Y = O (Orange)

Proceed:

B + V = BV;
R + V = RV;
Y + V = YV;

and etc: BO, RO, YO, BG, RG, YG - "expert" potions; Sandro can combine any type of potions and any number less or equal than 15;

Folowing to the state of this problem, we should consider any recipes of interesting final potion, and these recipes could include any of K <= 15 reagents - other potions; We also should recognize, what type of advanced potions Sandro can prepare, using his start reagents; And add new occasions into the answer.

Sry for English, but i think - w/o considering the above, actual solution isn't correct.

Edited by author 22.08.2011 01:36

Edited by author 22.08.2011 01:36

Please explain me this problem>Thank!!!

I think that this task describes the alchemy system from epic game M&M 8 (it's not 6 or 7, because in previous parts player couldn't play lich, but in 8 he could if he completed quest for necromancer). I love this game! Thanks to author, he caused nostalgia...

Tell me, if I made mistake truying to identify the game. :)

here my code:
#include<iostream>
using namespace std;
int main()
{
    int flag[3];
    int b,r,y;
    cin>>b>>r>>y;
    int n,i,j,k;
    char str[3][10];
    cin>>n;
    i=0;
    while(i<n)
        cin>>str[i++];
    for(i=0;i<n;i++)
    {
        if(str[i][0]=='B'||str[i][0]=='b')
            flag[0]=1;
        if(str[i][0]=='R'||str[i][0]=='r')
            flag[1]=1;
        if(str[i][0]=='Y'||str[i][0]=='y')
            flag[2]=1;
    }
    int sum=1;
    if(flag[0]==1)
        sum*=b;
    if(flag[1]==1)
        sum*=r;
    if(flag[2]==1)
        sum*=y;
    cout<<sum<<endl;
    return 0;
}

can anybody help me???