n = int (input())
cnt = 0
for i in range (n+1) :
    a = input()
    if a[-4:] != "+one" :
        cnt += 1
    if a[-4:] == "+one" :
        cnt += 2
if cnt != 11 :
    print ((cnt * 100) + 200)
if cnt == 13 :
    print ((cnt * 100) + 300)

Runtime error,what's wrong?

Edited by author 02.03.2022 22:29

import java.util.Scanner;

public class Task_2100 {
    public static void main(String[] args){
        Scanner scr1 = new Scanner(System.in);
        Scanner scr2 = new Scanner(System.in);

        int n, counter;
        n = scr1.nextInt();
        counter = n+2;
        while(n-- > 0){
            String guest = scr2.nextLine();
            String substring = "+";
            if(guest.contains(substring)){
                counter++;
            }
        }
        if(counter==13) {
            counter++;
        }
        System.out.print(counter*100);
    }
}

#include <iostream>

using namespace std;

int main()
{
int n, x=2;
cin>>n;
 x += n;
 while(n--)
    {
      string s;
      cin >> s;
        for(int i=0; i<s.size(); i++)
        {
            if(s[i]=='+')
            {
                x++;
            }
        }
    }
    if(x!=13)   cout << 100*x<< endl;
    else            cout << 100*(x+1) << endl;


   return 0;
}

Edited by author 25.03.2022 06:15

Edited by author 25.03.2022 06:15

#include <iostream>
#include <string>

int main() {
    int n, gCount = 2;
    std::cin >> n;
    std::string guest;

    while (n--) {
        std::cin >> guest;
        gCount++;
        if (guest.find("+one", 0) != std::string::npos) gCount++;
    }
    if (gCount == 13) gCount++;
    std::cout << gCount * 100 << std::endl;

    return 0;
}

$ Before going to the solution, make sure that you had tried enough, please.

$ Code:-

#include<bits/stdc++.h>
#define START int main(){
#define END system("PAUSE");return 0;}
using namespace std;

START

    int n, guest=2;
    cin >> n;
    guest += n;
    while(n--)
    {
        string s;
        cin >> s;
        for(int i=0; i<s.size(); i++)
        {
            if(s[i]=='+')
            {
                guest++;
            }
        }
    }
    if(guest != 13)
    {
        cout << 100*guest << endl;
    }
    else
    {
        cout << 100*(guest+1) << endl;
    }

END


///Thank You and Pray for me.

Edited by author 05.03.2020 17:01

#include <iostream>
#include <string>
using namespace std;
int main()
{
    int n,g=2;
    cin >> n;
    for(int i = 0; i < n; i++)
    {
        string a;
        cin >> a;
        if(a.length() > 4 && a.substr(a.length()-4,a.length()-1) == "+one")
            g+=2;
        else
            g++;
    }
    if(g == 13)
        cout << 1400;
    else
        cout << g*100;
}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    char name[20];
    int N;
    scanf("%d", &N);
    int cost=200;
    int $=0;
    for(int i=0; i<N; i++)
    {
        scanf("%s", name);
        if(name[strlen(name)-4]=='+'&&name[strlen(name)-3]=='o'&&name[strlen(name)-2]=='n'&&name[strlen(name)-1]=='e')
        {
            cost=cost+200;
        }
        else
        {
            cost=cost+100;
        }
    }
    $=$+cost;
    if($==1300)
    {
        $=$+100;
    }
    printf("%d", $);
    return 0;
}

a=int(raw_input())
count=2
for i in range(0,a):
    b=str(raw_input())
    if b[-4]=='+':
        count+=2
    else:
        count+=1
if count==13:
    count+=1
print(count*100)

f = int(input())
friends = []
cnt  = 0
for i in range(f):
    j = str(input())
    if j[-4:] == "+one":
        cnt += 200
    else:
        cnt+= 100
if ((cnt/100)+2) == 13:
    cnt += 300
else:
    cnt += 200

print(cnt)

I solve it by this

#include <iostream>
#include <string>
using namespace std;
int main()
{
    int n,i,k=2;
    string s;
    cin>>n;

    for (i=1;i<=n;++i)
    {
        getline(cin,s);
        if (s.find("+")!=string::npos)
        k+=2;

        else
        ++k;
    }

    if (k==13)
    ++k;

    cout<<k*100;

    return 0;
}

Edited by author 16.06.2019 18:08

Edited by author 16.06.2019 18:08

Когда использую циклы такого вида выдает ошибку Runtime error (non-zero exit code)

i=n;
while(i>0) {
    name[i]=calloc(1,30);
    scanf(" %s",name[i]);
    i--;
}
i=n;
while(i>0) {
    char *buf=name[i];
    while(*buf!='\0') {
        if(*buf=='+') {
            kol++;
            break;
        } else {
            buf++;
        }
    }
    i--;
}

А здесь AC
for(i=0;i<n;i++) {
    name[i]=calloc(1,30);
    scanf(" %s",name[i]);
}
for(i=0;i<n;i++) {
    char *buf=name[i];
    while(*buf!='\0') {
        if(*buf=='+') {
            kol++;
            break;
        } else {
            buf++;
        }
    }
}

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApp4
{
 class Program
 {
  static void Main(string[] args)
  {
            int n = Convert.ToInt16(Console.ReadLine());
            int s = 2;
            for (int i = 1; i<=n; i++)
            {
                string a = Console.ReadLine();
                if (a.Contains("+one"))
                    s += 2;
                else s++;
            }
            if (s == 13) s++;
            Console.WriteLine(s * 100);
  }
 }
}

What does it mean? Runtime error (access violation)
This is my code on c++
#include <iostream>
using namespace std;
int n,ans;
string s;
int main()
{
    cin>>n;
    ans=n+2;
    for(int i=0; i<n; i++)
    {
        cin>>s;
        for(int j=0; j<s.size()-3; j++)
        {
            if(s[j]=='+' && s[j+1]=='o' && s[j+2]=='n' && s[j+3]=='e')
            {
                ans++;
                break;
            }
        }
    }
    if(ans==13) ans++;
    cout<<100*ans;
    return 0;
}

Edited by author 31.05.2017 21:40

Set answer as (2+n).
Then n times repeat answer+="+one"in set(input()).
"+" in set(input ())  is also enough.

Problem had tied on the fact that i used tokeniser for numbers and buffered reader for strings,
Now i'm using bf reader for both strings and numbers and it gets AC.

I leave it here, maybe it will useful

Edited by author 05.03.2017 01:23