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| | | Show all threads     Hide all threads     Show all messages     Hide all messages |  | WA #2 | Marginean Ciprian | 2105. Alice and Bob are on Bikes | 15 Nov 2020 21:07 | 2 |  | WA #2 Marginean Ciprian 14 Nov 2018 22:19 Can you please give me a test for my code?For WA#2 you have to check if Alice/Bob are waiting exact amount di. I tried case when di=0, and noticed my code waits 1 time, instead of waiting for 0. |  | It's very beatyfull problem. Thanks | KostyaRychkov | 2105. Alice and Bob are on Bikes | 17 Aug 2020 22:53 | 1 |  |  |  | To admin, please,  fix the statement. | xurshid_n | 2105. Alice and Bob are on Bikes | 18 Apr 2017 12:26 | 2 |  | << When they “meet” (i.e., at some moment they are in the same point as in the PREVIOUS WERE NOT), they joyfully exclaim (“Oh, Bob!” or “Oh, Alice!” respectively).>>
 Let this test:
 L = 10   T = 10   va = 10  vb = 10
 n = 1  type = 1 t[1] = 0,  d[1] = 10.
 
 Alice and Bob "meet" 10 times at the SAME point,  so answer should be 1.
 But, AC solution gives 10.
>> at some moment they are in the same point
 >> at some moment
 
 there are different moments for their meeting
 |  | Что за 4 тест???? | simoncatcity | 2105. Alice and Bob are on Bikes | 9 Mar 2017 14:32 | 1 |  | Что за 4 тест??? не могу понять, где что неправильно... |  | Correct answer? | szczepi | 2105. Alice and Bob are on Bikes | 8 Dec 2016 19:27 | 2 |  | What answer should be for given test?
 1 1 1 1
 0
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