#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main() {
unsigned long long k[4];
for(int i=0;i<4;i++){
    scanf("%llu",&k[i]);

}
printf("\n");
printf("%.4f\n",sqrt(k[3]));
printf("%.4f\n",sqrt(k[2]));
printf("%.4f\n",sqrt(k[1]));
printf("%.4f\n",sqrt(k[0]));
  return 0;
}

Ошибка на тесте 2 /Error in test 2

Edited by author 09.09.2018 15:45

I tried hard and hard but was getting runtime error: access violation again and again because of not taking proper size of array. at last I used a[128*1024] by a solution of a discussion. and it worked. but how it was done? I mean I didn't get the clue line of question " A size of the input stream does not exceed 256 KB. "

can you help me?

I use
type[256*1024]
int main(){ ... }

run successfully .

but use struct as

int main()
{ type[256*1024] }

get error :  access violation

and use

type[256*1024 / sizeof(type)]

get error : access violation

what is the "A size of the input stream does not exceed 256 KB." means!

#include<stdio.h>
#include<math.h>

int main(){

    float i=0,racuad[61];
    int a=1,b=1;

    while(i<=pow(10,18)){
        racuad[a]=sqrt(i);
        a++;
        i=1+i*7843;
    }
    for(b=a-2;b>=0;b--){
        printf("%.4f\n",racuad[b+1]);
    }


    return 0;
}

#include <stdio.h>
#include <math.h>

void recur(void);

int main() {

    recur();
    return 0;
}

void recur() {
    long int num;
    scanf("%ld", &num);
    if (num != EOF)
        recur();
    printf("%.5f\n", sqrt(num));
}

Edited by author 09.08.2018 18:20

package timusreverseroot;

import java.text.DecimalFormat;
import java.util.*;
public class TimusReverseRoot {

    public static void main(String[] args) {
        DecimalFormat f = new DecimalFormat("#0.0000");
        Scanner keyboard = new Scanner(System.in);
        String inputs = keyboard.nextLine();
        String[] parsed = inputs.split(" ");

        for (String parsed1 : parsed) {
            int square = (int) Math.pow(Integer.parseInt(parsed1), 2);
            System.out.println(f.format(square));
        }
    }

}
I added in the package line but if I left that in, it would give me a compilation error, why is that? And this code runs perfectly fine in Netbeans but the judge gives a compilation error

Edited by author 07.05.2018 22:48

Edited by author 07.05.2018 22:49

import java.io.InputStreamReader;
import java.text.DecimalFormat;
import java.util.Scanner;

public class Reverse {

    private static void printer(double value){
        String pattern = "###0.0000";
        DecimalFormat myFormatter = new DecimalFormat(pattern);
        String output = myFormatter.format(value);
        System.out.println(output);
    }
    public static void main(String[] args) {
        Scanner sc = new Scanner(new InputStreamReader(System.in));
        long a,b,c,d;

        a = sc.nextLong();
        b = sc.nextLong();
        c = sc.nextLong();
        d = sc.nextLong();

        printer(Math.sqrt(d));
        printer(Math.sqrt(c));
        printer(Math.sqrt(b));
        printer(Math.sqrt(a));
    }
}

https://ideone.com/Ocpa4V

I can't figure out what's wrong with my code. I used 'Queue' data structure.

Edited by author 23.01.2018 16:02

#include<stdio.h>
#include<math.h>
#define size 256*1024/sizeof(long long)
int main()
{
  int s=0,l;
  long long int a[size+1];
  do{l=scanf("%lld",a[s++]);}while(l!=EOF);
  for(s=s-2;s>=0;s--)
     printf("%.4Lf\n", sqrt((double)a[s]));

}

"отделённых друг от друга ПРОИЗВОЛЬНЫМ КОЛ-ВОМ пробелов и переводов строк" - это меня "убивает"...

По сути ведь получается, что непонятно, когда заканчивается ввод исходных данных. Не так ли?

Или я могу чего-то не знать?
<python>

#include "stdafx.h"
#include<stdio.h>
#include<math.h>

int _tmain(int argc, _TCHAR* argv[])
{
    float a;
    scanf_s("%f", &a);
    printf_s("%6.4f", sqrt(a));
    scanf_s("%f", &a);
    return 0;
}

#include<stdio.h>
#include<math.h>
#define n 4
int main(){
int a[n]={100000000};
int i;

for(i=0; i<n; i++)
scanf("%d", &a[i]);

for(i=n; i>0; i--){
   printf("%.4f\n", sqrt(a[i]));}

return 0;
}

#include<stdio.h>
#include<math.h>
#define n 4
int main(){
int a[n]={100000000};
int i;

for(i=0; i<n; i++)
scanf("%d", &a[i]);

for(i=0; i<n; i++){
   printf("%.4f\n", sqrt(a[i]));}

return 0;
}

import java.util.Scanner;
import java.util.Stack;

public class ReverseRoot_SplitDecimal {

    public static void main(String args[]) {

        Scanner sc = new Scanner(System.in);
        Stack<Integer> integerNumberStack = new Stack<Integer>();
        Stack<Short> floatingNumberStack = new Stack<Short>();

        Double tempDouble = new Double(0);

        while(sc.hasNextInt()) {
            tempDouble = Math.sqrt(sc.nextDouble());
            integerNumberStack.push(Integer.parseInt(String.format("%.4f", tempDouble).split("\\.")[0]));
            floatingNumberStack.push(Short.parseShort(String.format("%.4f", tempDouble).split("\\.")[1]));
        }

        while(!integerNumberStack.isEmpty()) {
            System.out.printf("\n%d.%04d", integerNumberStack.pop(), floatingNumberStack.pop());
        }
        System.out.println();

        sc.close();
    }
}

Can anyone explain why this is saying wrong answer?

namespace Ex2
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] input = Console.ReadLine().Split(new char[] { ' ', '\t' }, StringSplitOptions.RemoveEmptyEntries);

            for (int a = input.Length - 1; a >= 0; a--)
            {
                double temp = Math.Sqrt(double.Parse(input[a]));

                if (temp == 0)
                {
                    string zero = temp.ToString();
                    zero += ",";
                    Console.WriteLine(zero.PadRight(6,'0'));
                }
                else
                {
                    Console.WriteLine(temp);
                }
            }

            //Console.ReadLine();
        }
    }
}

import java.util.Scanner;

public class main {
    public static void main(String[] args) throws Exception {

        Scanner scan = new Scanner(System.in);

        String a = scan.nextLine();
        double b = Double.parseDouble(a);
        double c;
        double d = b;

        double mass[] = new double[(int)b];

        while (b != 0) {
            c = Math.sqrt(scan.nextDouble());
            mass[(int)(b - 1)] = c;
            b--;
        }
        for (double i = 0; i < d; i++) {
            System.out.printf("%.4f\n", mass[(int)i]);
        }
    }
}

Outputs "Runtime error"

Edited by author 09.10.2017 00:50

#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#define SIZE 128*1024
int main()
{
    int i,n=0;
    long long int num[SIZE],N;

printf("enter your aray value:\n");
    while(scanf("%lld",&N)!=EOF)
          {
              num[n]=N;
            n++;
        }

    for(i=n-1;i>=0;i--){

      printf("%0.4lf\n",(double)sqrt(num[i]));
    }
    return 0;
}

from re import *
from math import sqrt

result = findall('[0-9]+', input())
result.reverse()

for i in result:
    print('{:.4f}'.format(sqrt(int(i))))

Edited by author 14.03.2017 01:20

import java.util.Scanner;

public class JavaApplication12 {

    public static void main(String[] args) {


    double x,k;
    int a;
    double y =Math.pow(10,18);


System.out.println("Сколько хотите ввести чисел ? ");
Scanner sc = new Scanner(System.in);
a = sc.nextInt();
int arr[] = new int[a];

for(int j=0;j<a;j++)
{

    do
{
        arr[j] =(int) sc.nextLong();
}

 while (arr[j]<0 || arr[j]>y);

}

for(int i=a-1;i>=0;i--)
{

    k = Math.sqrt(arr[i]);
    System.out.println(k);

}



  }
}