Help!


var
  p,q:extended;
  n,i:longint;
  b:boolean;
begin
  readln(p);
  readln(q);
  p:=p*0.01;
  q:=q*0.01;
  n:=0;b:=false;
  repeat
    inc(n);
    for i:=1 to n do
      begin
        if ((i/n)>=p) and ((i/n)<=q)
          then begin
                 b:=true;
                 write(n);
                 exit;
               end;
      end;
  until b=true;
end.

var
  p,q,q1:real;
  i,p1:integer;
  f:boolean;
begin
  read(p); read(q);
  p:=p/100; q:=q/100;
  f:=true; i:=1;
    while f do begin
                 inc(i);
                 p1:=trunc(p*i)+1;
                 q1:=q*i;
                 if (p1<q1) then f:=false;
               end;
     writeln(i);
end.

#include <cstdio>
void main (){
    int res= 0, a1, a2;
    double p, q;
    scanf ("%lf%lf", &p, &q);
    do{
        res ++,a1= (int)(p* (double)res)/100, a2= (int)(q* (double)res-(1e-7))/100;
    }while (a1== a2);
    printf ("%d\n", res);
}

#include <cstdlib>
#include <iostream>
#include <iomanip>

using namespace std;

int main(int argc, char *argv[])
{

    double a,b,c,d,m,n=2,mn;
    cin>>a>>b;
    c=a/100;
    d=b/100;
    while (1)
    {m=1;
     while (m<n)
    {mn=m/n;
     if ((mn<d)&&(mn>c)) break;
     m++;}
     if (m!=n) break;
     n++;}
     cout<<n<<endl;
    system("PAUSE");
    return EXIT_SUCCESS;
}




This is my project Got WA on test14.
I think there's something wrong with digits
But i cannot find it
Can anyone help me with it?
Thx!

My best execution time is 0.015s, how can I improve the performance?

Thanks a lot!

1、Use extended,not real,and you'll get AC.
If you want to know why,you can readln some real like 100/100 and use WATCH to check it in the program.You may find that the number change to someting like"1.0000000001"or"0.99999999998".

2、Take care of the description:less than q%.Less than!!!!
So:if trunc((i*q/100))=(i*q/100) then continue;

is it possible p = q?
what should I output when q = p?
q = 10
p = 10
result 0 or 10? thanks

http://tieba.baidu.com/f?kz=632211990

I can't understand the problem well

Whats wrong with my code?

#include <stdlib.h>
#include <math.h>
#include <vector>
#include <iostream>
#include <string>
#include <fstream>
#include <algorithm>
#include <utility>
#include <stdlib.h>
#include <set>

using namespace std;

bool normal (float, float);

int main() {
    float begin, end, y1, y2;
    int counter = 1;

    scanf ("%f %f", &begin, &end);

    do{
        y1 = (begin*counter)/100;
        y2 = (end*counter)/100;
        if (normal(y1, y2)){
            printf ("%i\n", counter);
            return 0;
        }
        counter++;
    } while (true);

    return (0);
}

bool normal (float a, float b){
    if (ceil(a)<=(float)b) return true;
    else return false;
}

Can somebody tell me hints to this problem? What can be with this test?

I didn´t understand the anwser.
How 15? If there are 15 citzens, what are the possible numbers of conductors?

Thanks,

Pedro.

#include <stdio.h>
#include <math.h>
#include <iostream>
int det(const double a,const double b)
{
    int i = (int)a;
    double x = floor(a*10000)/10000;
    while (i<x)i++;
    if (i>=1&&i<b&&i>x)return 1;
    else return 0;
}
int main()
{
    double p,q;
    int c;

    scanf("%lf%lf",&p,&q);
    p = 100 / (p);
    q = 100 / (q);
    for (c=1;det(c*q ,floor(c*p+0.00001)) == 0 ;c++);
    printf("%.0lf\n", c*q );
    return 0;
}

I don't know why i keep getting WA. I tried many things but still WA. How can i get the test data? I remember that timus had a feature of sending an email with detailed data, but i can't find it anymore.

apparently default culture on the server is such, that double as a string looks like 14,14 not 14.14. So Convert.ToDouble(input) will throw exception. To fix this use CultureInfo:
CultureInfo ci = new CultureInfo("en-us");
low = Convert.ToDouble(input[0], ci);

i don't know what this problem say.
it's AMBIGUOUS for me.

here my program
what is the problem.
tired of changing it.
WA test#6:

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    float p,q;
    long long int n=1;
    cin>>p>>q;
    p/=100.0;
    q/=100.0;
    while(ceil(n * q + 1e-9)-ceil(n*p + 1e-9)<1.0)
        n++;
    cout<<n;
    return 0;
}