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Show all threads Hide all threads Show all messages Hide all messages | wa 10 | 👑TIMOFEY👑 | 1401. Gamers | 10 Mar 2024 19:20 | 3 | wa 10 👑TIMOFEY👑 30 Oct 2022 13:33 Re: wa 10 vtalgo24_Zakusov_367223 10 Mar 2024 19:18 wa 10 output for "3 3 2": 1 1 2 2 8 8 6 6 1 5 5 2 8 10 10 6 3 0 5 4 9 9 10 7 3 3 4 4 21 9 7 7 12 12 14 21 21 19 18 18 12 15 14 14 19 19 20 18 11 15 15 13 17 20 20 16 11 11 13 13 17 17 16 16 Re: wa 10 vtalgo24_Zakusov_367223 10 Mar 2024 19:20 no overflow, checked all cases for n \in {1, 2, 3} | wa 10 | 👑TIMOFEY👑 | 1401. Gamers | 30 Oct 2022 13:32 | 1 | wa 10 👑TIMOFEY👑 30 Oct 2022 13:32 | help!!!! | Olim Nazarov | 1401. Gamers | 27 Jan 2012 23:54 | 2 | | There is some inaccuracy in the condition.In condition is writed:'The second line consist two integers x and y'. I write readln(x,y) and got WA#4. When I changed it to readln(y,x), I got AC. | Partisan | 1401. Gamers | 19 Jun 2009 19:51 | 9 | Are you sure? Probably you write for i:=1 to x for j:=1 to y In this case you should switch x and y. I had WA#4 for 3 times, than I replaced scanf("%d %d %d", &n, &x, &y); with scanf("%d %d %d", &n, &y, &x); and got AC! But I'm sure that there is a mistake in tests cuz I think that the first version of my program was right. :-| I also had wa#4 before changing readln(x,y) to readln(y,x)! but now i have AC If some inaccurate statement need to be fixed, it's better to write about it to timus_support@acm.timus.ru instead of webboard. I hadn't change x and y, but I still got AC. Maybe something wrong with your program. Read problem statement more careful: The second line consists of two integers x and y — those are the coordinates of the deleted cell (1 <= x, y <= 2n). X is a number of a LINE and Y — a number of a ROW. Yep, and both LINE and ROW usually refer to something horizontal (along with Y coordinate) :) That should be rows/columns for clearer problem statement. | WA #3 | Xysia | 1401. Gamers | 24 Jul 2008 17:48 | 7 | WA #3 Xysia 4 Apr 2008 14:00 OK, I had a mistake in zeroing the matrix at the beginning setup. Now I have AC. Edited by author 23.02.2009 21:24 Tested for input (on my computer): 3 4 5 this program gave me result: 3 3 4 4 8 8 9 9 3 2 2 4 8 7 7 9 5 2 6 6 10 10 7 11 5 5 6 1 1 10 11 11 13 13 14 0 1 18 19 19 13 12 14 14 18 18 17 19 15 12 12 16 20 17 17 21 15 15 16 16 20 20 21 21 I don't see anything wrong here. Maybe I haven't fully and correctly understood the problem? Edited by author 11.04.2008 21:42 your num 0 isn't on the correct place So you mean that I have switched rows and columns? Well, now I have changed the scanf line from (...) &a,&b) to (...) &b,&a) and now I have the following result for this test: 3 3 4 4 8 8 9 9 3 2 2 4 8 7 7 9 5 2 6 6 10 10 7 11 5 5 6 1 0 10 11 11 13 13 14 1 1 18 19 19 13 12 14 14 18 18 17 19 15 12 12 16 20 17 17 21 15 15 16 16 20 20 21 21 But I still have WA #3 :( Also, look at the other posts at the forum about this problem and you'll read that people who have exchanged rows with columns have WA #4. I have WA earlier so there must be something else wrong with my program... :( So, could somebody give the correct solution for test: 3 4 5 ? Maybe I haven't correctly understood this problem? 3 3 4 4 8 8 9 9 3 2 2 4 8 7 7 9 5 2 6 6 10 10 7 11 5 5 6 1 0 10 11 11 13 13 14 1 1 18 19 19 13 12 14 14 18 18 17 19 15 12 12 16 20 17 17 21 15 15 16 16 20 20 21 21 x is row, y is column, I was caught by that (but AFAIK it wasn't WA3) |
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