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| Показать все ветки Спрятать все ветки Показать все сообщения Спрятать все сообщения | | wa 10 | 👑TIMOFEY👑 | 1401. Игроки | 10 мар 2024 19:20 | 3 | wa 10 👑TIMOFEY👑 30 окт 2022 13:33 Re: wa 10 vtalgo24_Zakusov_367223 10 мар 2024 19:18 wa 10
output for "3 3 2":
1 1 2 2 8 8 6 6
1 5 5 2 8 10 10 6
3 0 5 4 9 9 10 7
3 3 4 4 21 9 7 7
12 12 14 21 21 19 18 18
12 15 14 14 19 19 20 18
11 15 15 13 17 20 20 16
11 11 13 13 17 17 16 16 Re: wa 10 vtalgo24_Zakusov_367223 10 мар 2024 19:20 no overflow, checked all cases for n \in {1, 2, 3} | | wa 10 | 👑TIMOFEY👑 | 1401. Игроки | 30 окт 2022 13:32 | 1 | wa 10 👑TIMOFEY👑 30 окт 2022 13:32 | | help!!!! | Olim Nazarov | 1401. Игроки | 27 янв 2012 23:54 | 2 | | | There is some inaccuracy in the condition.In condition is writed:'The second line consist two integers x and y'. I write readln(x,y) and got WA#4. When I changed it to readln(y,x), I got AC. | Partisan | 1401. Игроки | 19 июн 2009 19:51 | 9 | Are you sure?
Probably you write
for i:=1 to x
for j:=1 to y
In this case you should switch x and y. I had WA#4 for 3 times, than I replaced
scanf("%d %d %d", &n, &x, &y);
with
scanf("%d %d %d", &n, &y, &x);
and got AC! But I'm sure that there is a mistake in tests cuz I think that the first version of my program was right. :-| I also had wa#4 before changing readln(x,y) to readln(y,x)!
but now i have AC If some inaccurate statement need to be fixed, it's better to write about it to timus_support@acm.timus.ru instead of webboard. I hadn't change x and y,
but I still got AC.
Maybe something wrong with your program. Read problem statement more careful:
The second line consists of two integers x and y — those are the coordinates of the deleted cell (1 <= x, y <= 2n). X is a number of a LINE and Y — a number of a ROW. Yep, and both LINE and ROW usually refer to something horizontal (along with Y coordinate) :) That should be rows/columns for clearer problem statement. | | WA #3 | Xysia | 1401. Игроки | 24 июл 2008 17:48 | 7 | WA #3 Xysia 4 апр 2008 14:00 OK, I had a mistake in zeroing the matrix at the beginning setup.
Now I have AC.
Edited by author 23.02.2009 21:24 Tested for input (on my computer):
3
4 5
this program gave me result:
3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 1 10 11 11
13 13 14 0 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21
I don't see anything wrong here. Maybe I haven't fully and correctly understood the problem?
Edited by author 11.04.2008 21:42 your num 0 isn't on the correct place So you mean that I have switched rows and columns?
Well, now I have changed the scanf line from
(...) &a,&b) to
(...) &b,&a)
and now I have the following result for this test:
3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 0 10 11 11
13 13 14 1 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21
But I still have WA #3 :(
Also, look at the other posts at the forum about this problem and you'll read that people who have exchanged rows with columns have WA #4. I have WA earlier so there must be
something else wrong with my program... :( So, could somebody give the correct solution for test:
3
4 5
? Maybe I haven't correctly understood this problem? 3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 0 10 11 11
13 13 14 1 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21
x is row, y is column, I was caught by that (but AFAIK it wasn't WA3) |
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