import java.util.*;
public class LuckyNumber{
 public static void main(String args[]){
Scanner in = new Scanner(System.in);
int x = in.nextInt();
 int a1,a2,a3,b1,b2,b3;
a1 = x/100000; a2 = (x/10000)%10; a3 = (x/1000)%10;
b1 = (x/100)%10; b2 = (x/10)%10; b3 = x%10;
     if((a1+a2+a3) == (b1+b2+b3)) System.out.println("Lucky Number");
 else if(a1+a2+a3-(b1+b2+b3)>1 ||(b1+b2+b3)-(a1+a2+a3)>1) {
     System.out.println("prostoi bilet");
 }
else System.out.println("Lucky Number budet sleduwii ili prediduwi bilet");
     }
        }

"either the previous or the next ticket is lucky." and "one step from happiness"

lucky means: previous OR next, sum of first three digits EQUAL sum of last three digits.

Edited by author 03.10.2012 20:54

 Test #01 куда тут ошибка помогите пожалуйста
#include <iostream>
using namespace std;
int main ()
{
    short int A[6];
    signed  int s=0,s2=0;
    for (int i=0;i<6;i++)
    cin>>A[i];
    for (int i=0;i<3;i++)
     s=s+A[i];
    for (int i=5;i>=3;i--)
     s2=s2+A[i];

     if ((s-s2==-1)  || (s-s2==1 && A[5]!=9))
     cout<<"Yes";

     else
     cout<<"No";
    //system ("pause");

    return 0;

    }

Edited by author 22.06.2012 19:44

either the previous or the next ticket is lucky ---- > what does the lucky means ? can anyone give me an example?

 why a programe crash?

Now, I could be saying something stupid here.  But I think we're missing a definition of what happens at the topmost boundary.
Say our number is 999,999, if you subtract one, you don't get a lucky number, but if you add one, then what happens?
The problem said that it was going to be a 6 digit number at all times, but if you add one, it becomes a seven digit number, so does this case never occur?  And if it does, then does the lucky number formula apply only to the last 6 digits of the number?

this is my code, but wa in test 1, why?
what is the test 1,
thanks
sorry my english is very poor
    import java.io.*;
    import java.util.*;

    public class Main{


        static int sum(int n)
        {
            int sum=n%10+(n/10)%10+(n/100)%10;
            return sum;
        }

        static boolean solve(String n)
        {
            String ant=n.substring(0,3);
            String post=n.substring(3,6);
            if(ant.compareTo(post)==0)
               return true;
            else
            {

            int antn=Integer.parseInt(ant);
            int postn=Integer.parseInt(post);

            int a;
            int b;
            int c;
            int d;
            if(postn+1>999)
            {
                a=antn+1;
                b=0;
            }
            else
            {
                a=antn;
                b=postn+1;
            }
            if(postn-1<0)
            {
                c=antn-1;
                d=999;
            }
            else
            {
                c=antn;
                d=postn-1;
            }
            a=sum(a);
            b=sum(b);
            c=sum(c);
            d=sum(d);

            if(a==b||c==d)
               return true;
            else
             return false;
            }
        }


        public static void main (String args[])
        {
            Scanner in=new Scanner(System.in);
            String n;
            while(in.hasNext())
            {
              n=in.next();
              if(solve(n))
                System.out.println("YES");
              else
                System.out.println("NO");
            }
        }
    }

var a,b,c,d,e,f,g,r,v:integer;
begin
 while(true)do begin
read(a);
r:=a+1;
v:=a-1;

  b:=r mod 10;
  c:=(r mod 100) div 10;
  d:=(r mod 1000) div 100;
  e:=r div 100000;
  f:=(r div 10000)mod 10;
  g:=(r div 1000)mod 10;
  if (b+c+d=e+f+g) then begin write('Yes') ; break;end;

  b:=v mod 10;
  c:=(v mod 100) div 10;
  d:=(v mod 1000) div 100;
  e:=v div 100000;
  f:=(v div 10000)mod 10;
  g:=(v div 1000)mod 10;
  if (b+c+d=e+f+g)  then write('Yes') else write('No');


break;
end;
 end.

Edited by author 09.11.2011 15:46

Can anyone tell me what the test #6 is? In my opinion the solution is correct, but it gives wa on test #6... And also, if the number is 999999 it should take as the next number 000000 or it should consider, that there is no next number and print "No"??? The same for 000000?

this is my solution



#include<iostream>
using namespace std;
int main()
{
    int n,a,b,c,d,s1=0,s2=0;
    cin>>n;
    a=n;

    n=a+1;
    s1+=n%10;n=n/10;
    s1+=n%10;
    n=n/10;
    s1+=n%10;n=n/10;

    s2+=n%10;n=n/10;
    s2+=n%10;n=n/10;
    s2+=n%10;n=n/10;
    if(s1==s2)b=1;
n=a-1;s1=0;s2=0;

if(n==1)    cout<<"YES";
else {
s1+=n%10;n=n/10;
    s1+=n%10;
    n=n/10;
    s1+=n%10;n=n/10;

    s2+=n%10;n=n/10;
    s2+=n%10;n=n/10;
    s2+=n%10;n=n/10;
    if(s1==s2)b=1;
}
if(b==1)cout<<"YES";
else cout<<"NO";


}

715068 Yes          7+1+5=13  0+6+8=14
445219 No           4+4+5=13  2+1+9=12     <<<---- Why ANSWer is No ? ? ?
012200 Yes          0+1+2=3   2+0+0=2

WTF ?

Edited by author 25.07.2011 00:19

Edited by author 25.07.2011 02:11

Edited by author 17.10.2010 20:13

Mind the tests
000000 and 999999
999999+1 and 000000-1 don't belong to the definition of ticket

var a:array[1..6]of integer;
    i:integer;
    g:char;
    s:string;
begin
read(s);
for i:=1 to 6 do
val(s[i],a[i],g);
if (a[6]<>9) and
((a[1]+a[2]+a[3]=a[4]+a[5]+a[6]+1)or
(a[1]+a[2]+a[3]=a[4]+a[5]+a[6]-1))then
writeln('Yes') else writeln('No');
end.

my code is
#include<stdio.h>
#include<string.h>
int main()
{
    char a[10];
    while(scanf("%s",a)==1)
    {
        long int s1=0,s2=0;
        long int len = strlen(a);
        for(long int i=0;i<len;i++)
        {
            if(i<3)
                s1 = s1 + (a[i]-'0');
            else
                s2 = s2 + (a[i] - '0');
        }
        long int sub = s1 - s2;

        if(sub ==1 || sub== -1)
        {
            if(sub==1)
            {
                long int add = (a[len-1]-'0')+1;
                if(add>9)
                {
                    printf("No\n");
                }
                else
                printf("Yes\n");
            }
            else if(sub == -1)
            {
                if(a[len-1]<1)
                printf("No\n");
                else
                printf("Yes\n");
            }
        }
        else
            printf("No\n");
    }
    return 0;
}

i don't know where is my problem. please help me.

Edited by author 06.11.2009 02:55

I couldn't understand the statements.

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

        int[] ints = ReadInts(in);

        int first = ints[0] + ints[1] + ints[2];
        int second = ints[3] + ints[4] + ((ints[5] == 9) ? 1 : ints[5] + 1);
        int third = ints[3] + ints[4] + ((ints[5] == 0) ? 8 : ints[5] - 1);

        System.out.println((first == second) || (first == third) ? "YES" : "NO");
    }

    public static int[] ReadInts(BufferedReader in) throws IOException {
        int[] result = new int[6];

        String input = in.readLine();

        for (int i = 0; i < input.length(); i++) {
            result[i]=Integer.parseInt(input.substring(i, i + 1));
        }

        return result;
    }
}

Please, give me some tests, i don't know, what wrong in my program(