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Обсуждение задачи 1582. БукмекерыD4nick 2 lines programm, lol. It's not difficult at all [1] // Задача 1582. Букмекеры 9 окт 2020 00:40 Hristo Nikolaev (B&W) Re: 2 lines programm, lol. It's not difficult at all // Задача 1582. Букмекеры 24 мар 2023 00:33 It can be at least 3 lines of code if you write one statement per line (in plain C) double k1, k2, k3; scanf("%lf %lf %lf", &k1, &k2, &k3); printf("%.0lf", /* The Expression */); Edited by author 24.03.2023 00:40 Mickkie k1 k2 k3 range from 0.01 to 100?? // Задача 1582. Букмекеры 12 янв 2013 09:59 from the betting coefficient k is (m + n) / n I think k must be greater than 1. Don't you think so? SKYDOS [Vladimir SU] To Admins - TLE 5. Wrong input data [2] // Задача 1582. Букмекеры 10 авг 2010 13:53 First I used my own method for reading data, this function: http://paste.ubuntu.com/475799/ GOT TLE 5... Then used this method: double[] data = Console.ReadLine().Split().Select(s => double.Parse(s)).ToArray(); GOT AC... Whats the 5 test? is it bug in my reading function or what? Need help. PS Check last @Crash@: http://acm.timus.ru/status.aspx?space=1&num=1582&author=73720 Code: if (data[0].IndexOf('.') == -1 || data[1].IndexOf('.')==-1 || data[2].IndexOf('.')==-1) throw new System.DivideByZeroException(); Some of numbers are NOT with floating point. From problem statement: В единственной строке через пробел записаны 3 числа с плавающей точкой k1, k2 и k3. Edited by author 10.08.2010 14:02 Vladimir Yakovlev (USU) Re: To Admins - TLE 5. Wrong input data [1] // Задача 1582. Букмекеры 10 авг 2010 21:18 100 - is the floating point number too. Andrew Hoffmann aka SKYDOS [Vladimir SU] Re: To Admins - TLE 5. Wrong input data // Задача 1582. Букмекеры 10 авг 2010 21:22 I think it should be "100.0" Vladimir Yakovlev (USU) писал(a) 10 августа 2010 21:18 100 - is the floating point number too. Narek X Can I solve this problem for time 0.001??Sory for bad english. [3] // Задача 1582. Букмекеры 6 сен 2009 14:35 Edited by author 06.09.2009 21:29 Svyatoslav [Vologda Multiple-Discipline Lyceum] Re: As I can solve this problem for time 0.001??Sory for bad english. // Задача 1582. Букмекеры 6 сен 2009 21:25 Equation Edited by author 06.09.2009 21:26 Svyatoslav [Vologda Multiple-Discipline Lyceum] Re: As I can solve this problem for time 0.001??Sory for bad english. [1] // Задача 1582. Букмекеры 6 сен 2009 21:25 Algorithm for this problem is O(1). You should to think a little. Narek X Re: As I can solve this problem for time 0.001??Sory for bad english. // Задача 1582. Букмекеры 6 сен 2009 21:33 My algorithm is O(1) and it is AC, but in 0.015 why??? Tural Neymanov I am the greatest :) [1] // Задача 1582. Букмекеры 28 авг 2008 02:37 Yes I did it! This problem wasn't solved by me, first, but after a few lists of paper i saw how stupid this problem is! and of course i feel honored because of my own solution! bsu.mmf.team Re: I am the greatest :) // Задача 1582. Букмекеры 18 сен 2008 19:52 GRATZ! =) Yashar Abbasov I didn't understand... [4] // Задача 1582. Букмекеры 27 окт 2007 18:31 Hi. Sorry can you explain me the second sample test. 1.25 10.0 5.75 ? How much money has he put for each of coefficients. Mace(Lviv Polytechniс NU) Re: I didn't understand... [3] // Задача 1582. Букмекеры 27 окт 2007 22:12 Just solve this system: k1*x1==k2*x2==k3*x3 x1+x2+x3==1000 svr Re: I didn't understand... // Задача 1582. Букмекеры 27 окт 2007 22:21 Man interested why so. Simply if examply k1*x1>max(k2*x2,k3*x3) we will lost in case of mistake with first result. Edited by author 27.10.2007 22:22 Edited by author 27.10.2007 22:23 Wang Fei Re: I didn't understand... // Задача 1582. Букмекеры 12 фев 2008 18:24 but isn't it to print k1*x1? Wang Fei Re: I didn't understand... // Задача 1582. Букмекеры 12 фев 2008 18:33 oh,i understand~~
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