#include <iostream>

using namespace std;



int main(){
int a,b = 0,c = 0,d = 0;
int ocenki[20];
cin » a;

for (int i = 1; i <= a; i++) cin » ocenki[i];
for (int i = 1; i <= a; i++){
if (ocenki[i] == 5){
b++;
}
else if (ocenki[i] == 4){
c++;
}
else if (ocenki[i] == 3){
d++;
}
}
if (d > 0){
cout « "None" « endl;
}
else if (b == a){
cout « "Named" « endl;
}
else if (c > b){
cout « "Common" « endl;
}
else if (c = b){
cout « "High" « endl;
}
return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int m[10]{}, n;
    cin >> n;
    int sum = 0;
    for (int i = 0; i < n; i++)
    {
        cin >> m[i];
        sum += m[i];
    }
    double q;
    q = static_cast<double>(sum) / n;
    if (q == 4)
    {
        cout << "Common";
    }
    if (q > 4.5 && q < 5)
    {
        cout << "High";
    }
    if (q == 5)
    {
        cout << "Named";
    }
    if (q == 3)
    {
        cout << "None";
    }
}

if u wanna break your programm type sys.exit() (don't forget to type import sys in the beginning of the programm)
_____________________
если вы хотите полностью прервать вашу программу, то импортируйте библиотеку sys и пропишите sys.exit()

It took me a while to get this one correct, and it's because I found part of the descritpion to be ambiguous/unclear - so I'm posting this clarification which hopefully will help anyone else who has the same misunderstanding.

"if a student has got satisfactory marks, the scholarship is not given, "

I read this to mean "got ONLY satisfactory marks" but my solutions were rejected.
Once I modified my solution to treat it as "got ANY satisfactory marks", the solution was accepted.

dont use ',' use '.' at 4.5

Please read "if a student has got satisfactory marks, the scholarship is not given" this statement again and again which means if in any of the subject a student gets 3.0 he will not get any scholarship.

--------------------------------------------------
Пожалуйста, прочитайте «если студент получил удовлетворительные оценки, стипендия не предоставляется», это утверждение снова и снова означает, что если по какому-либо предмету студент получает 3,0 балла, он не получит стипендию.

a = []
d = 0
for i in range(int(input())):
    a.append(input())
c = set(a)
for i in range(len(a)):
    if a[i] =='3':
        print('None')
        break
    if len(c) == 1 and a[0] == '5':
        print('Named')
        d = 0
        break
    for x in a:
        d += int(x)
    if len(c) != 1 or a[0] != '5' and d // len(a) >= 4.5:
        print('High')
        break
    else:
        print('Common')
        break
в чем ошибка

Can someone give 5^th test?
I got WA5;

var n,i,o,c,p,x:integer;
     s:real;
begin
s:=0;p:=0;
readln(n);
for i:=1 to n do begin
readln(o);
s:=s+o;
end;
s:=s/n;
if o = 3 then begin
inc(c);
writeln('None');
end;
if s=5 then if (c<>1) then begin
     inc(p);
     writeln('Named');end;
if s>=4.5 then if (c<>1)and (p<>1) then begin
inc(x);
writeln('High'); end;
if (c<>1) and (p<>1) and (x<>1) then
writeln('Common');
end.

Edited by author 05.04.2018 22:47

#include<stdio.h>
int main()
{
    int n , m , sum=0 ;
    double ava;
    scanf("%d",&n);
    int mark[11];
    for(m=0;m<n;m++){
        scanf("%d",&mark[m]);    }
    for(m=0;m<n;m++){
        sum=sum+mark[m];
    }
    ava=(double)sum/n;
    if(ava<=3)printf("None\n");
    else if (ava>=5)printf("Named\n");
    else if(ava>=4.5)printf("High\n");
    else printf("Common\n");
}

#include <stdio.h>
#include <stdlib.h>

int main()
{

    int a,p=0,i,*b;
float f,s=0;
scanf("%d",&a);
b=(int *)malloc(sizeof(int)*a);
for(i=0;i<a;i++){
scanf("%d",&b[i]);}
/*if (b[i]<3||b[i]>5)
    scanf("%d",&b[i]);
}*/
for(i=0;i<a;i++)
    s+=b[i];

f=s/a;
for(i=0;i<a;i++)
{

 if(b[i]==3){
 p=1;}
}

if(f==5)
   {printf("Named");
   }

       else if(f>=4.5&&p==0){ printf("High");
    }

        else if(f<4.5&&p==0){
    printf("Common");}
    else {printf("None");}
    free(b);
    return 0;
}

//I have correct in the IDE, what's wrong?

import java.io.IOException;
import java.util.Scanner;

public class VasyaCare{
    public static void main(String[] args) throws IOException {
    VasyaCare vasya_care = new VasyaCare();
    Scanner scn = new Scanner(System.in);
    int n = scn.nextInt();
    try{                               // Check
            if(n < 10){
        double[] b = vasya_care.setScore(n);
        double median = vasya_care.getMedian(b);
        if(median==3){
            System.out.println("None");
        }
        else if(median==5){
            System.out.println("Named");
        }
        else if(median >= 4.5){
            System.out.println("High");
        }
        else if(median < 4.5){
            System.out.println("Common");
        }
        }
        else throw new IOException("Please, type number from 1 to 10!");
    }
    catch(Exception e){e = new IOException();}
    }


    double getMedian(double[] b{          // calculate median score of exam
    int sum = 0;
    for(int i = 0; i < b.length; i++){
        sum = (int) (sum + b[i]);
    }
    return (double)sum/b.length;
    }

    double[] setScore(int n){            // forming list scores
    Scanner scn = new Scanner(System.in);
    double[] b = new double[n];{
        for(int j = 0; j < n; j++){
            int m = scn.nextInt();
            if(m<3 || m > 5){
                System.out.println("Type score from 3 to 5: ");
                j--;
            }
            else if (m>=3 && m<=5){
                b[j] = m;
            }
        }
    }
    return b;
    }
}

// Thank you for your attention!

Named         avg =5
High          avg>=4.5 not contain 3   nooooote  that
Common             not  3 and less than 4.5
None            not all of the above

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int n,s=0;
bool f=0;
float t;
cin>>n;
int M[n];
for( int i=0;i<n;i++)
{
    cin>>M[i];
     s+=M[i];
     if(M[i]==3)
     f=1;
}
t=s/float(n);
if(s/n==5)

    cout<<"Named";

else
if(f==1 || t<4.5 )

    cout<<"None";

else
if(t>=4.5)

    cout<<"High";

}

I don't understand what's wrong with my code

#include <iostream>

using namespace std;

int main()
{
    int n,i,mark;
    double t,coun;
    coun=0.0;
    cin >> n;
    for (i=0; i<n; i++)
    {
        cin >> mark;
        if (mark==3) t=0;
        coun+=mark;
    }

    if (t)  {t=coun/n;}

    if (!t) { cout << "None";}

    if (t == 5)
    {
        cout << "Named";
    }
    else if (t >= 4.5)
    {
        cout << "High";
    }
    else if (t != 0)
    {
        cout << "Common";
    }

    return 0;
}

n=int(input())
l=[int(input()) for _ in range(n)]
items=sum(l)
n=float(n)
x=3.0
for i in l:
    try:
        i==x
        print ('None')
if items/n==5 and i!=x:
    print 'Named'

elif (4.5<=(items/n)<5)and i!=x:
    print 'High'

elif ((items/n)<4.5)and i!=x:
    print 'Common'

As easy as the problem this is, it took me 5 attempts to get it right only because the problem statement was unclear. Follow  the more clear statement posted underneath this post.

1)If a person has got satisfactory marks in any subject than answer will be "None".
2)If he has got marks greater than 5 in all sub than answer is "Named";
3)If average score greater 4.5 than High;
4)Else common.

I am not trying to spoil the question but I found statement little bit unclear.Hope thhis will help