Обсуждение @ 1367. Конфиденциально! @ Timus Online Judge

What answer for...

Послано Anatoliy 'Tolyan_NO' Tolstobroff 21 авг 2005 23:32

#+#
+#+
#+#

and

#|#
-#-
#|#

and

#-#
+#-
#+#

Re: What answer for...

Послано Vedernikoff Sergey 22 авг 2005 02:41

My AC program outputs:

10100
01100
11111
00110
00101

and

10100
01100
11111
00110
00101

and

11100
11100
11111
00110
00101

Re: What answer for...

Послано Anatoliy 'Tolyan_NO' Tolstobroff 23 авг 2005 02:48

I check this test but my program get Wa21.

WHO TAKE wa21 Please help me or give some good tests.

Re: What answer for...

Послано Anatoliy 'Tolyan_NO' Tolstobroff 24 авг 2005 02:33

Asked me answer for this

###
###
###

please.

Re: What answer for...

Послано Vedernikoff Sergey 25 авг 2005 19:34

My AC program outputs:

110110000
111111000
011011000
110110110
111111111
011011011
000110110
000111111
000011011

Re: What answer for...

Послано Anatoliy 'Tolyan_NO' Tolstobroff 25 авг 2005 22:45

thanks.
Now i got Wa22

What answer for

#-#

and fo

#
|
#

Not need help more.

Послано Tolstobrov_Anatoliy[Ivanovo SPU] 25 авг 2005 23:23

I got AC I am very Happy.

I find error.
this test

##.
#..
..#

Re: Not need help more.

Послано dimozzz 18 мар 2007 22:54

Answer is :
1111
1111
1111
1111

???

And what right for your test??

Послано 107th 25 авг 2007 14:01

I did it! Who has WA 22, remember that "For the sake of simplicity, you can assume that the photographed area is surrounded with the barrier of "+"-es."

Edited by author 25.08.2007 19:52

Обсуждение задачи 1367. Конфиденциально!