Discussion @ 1375. Bill Clevers @ Timus Online Judge

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Discussion of Problem 1375. Bill Clevers

x2 + y2 = k (mod p)

Posted by 4MG_TEAM 10 Sep 2005 16:22

x^2 + y^2 = k (mod p) shouldn't it be (x^2 + y^2) mod p = k

Re: x2 + y2 = k (mod p)

Posted by Black_Account 10 Sep 2005 18:47

Yes, it should be so. Can you help with E? :-)