#include <iostream.h>

bool next(unsigned long int n)
{
        for (unsigned short int i=9;i>1;i--)
            if (n%i==0&&(n/i>9?next(n/i):i+=n/i*10))
            {
                cout << i;
                return 1;
            }
        return 0;
}

int main()
{
   unsigned long int n;
   cin >> n;
   if (n<10)
       cout << (n==0?10:n);
   else
       if (!next(n))
           cout << -1;
   return 0;
}

Do you like it as much as i do? :)

I don't understand your solution. Can you explaint to me.

:) good good. I had the same approach when I read it at first.

Very easy solution.

Very nice, indeed. I wish i had thought of that :)
Nevertheless i've solved the problem in my own way :D