[deleted] I got Accept.

Edited by author 09.01.2007 23:57

a=1, b=1, c=31 =>
z = 2^30+1
x = (2*(2^30+1))^30 > 2^900 > 10^50
But in statements is said that answers should not exceed 10^50.

Thanks. I understood my mistake. But am I in a right way, or I must think about somethink else ?

Alright ;)
Just invent another one formula.
Mine produces numbers <= 2^31.

On right way... If you want, I could give you the true formula!!!

Thanks, but I got Accept:).Of course, if you want, you can help me with 1106, because after rejudging I had WA#11 :(

Post your mail, I'll try to help you.

Mail: w_soulreaver@ukr.net    Thanks.