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Обсуждение задачи 1201. Какой сегодня день?

Problem without problem statement!!!
Послано [SPbSU ITMO] MAKAPOB 3 мар 2007 11:35
To admins: please add some rules, which format of output should be, because this example from one month shows me nothing.
1) number of spaces must be 3 everywhere except 1,2,3,4,5,6,7,8,9?
2) we must count day of week using normal calender? Rules about it are full, or some items are omitted???
3) What is in test 10??
P.S.
Is this correct for: 7 1 2006

mon.......2....9...16...23...30
tue.......3...10...17...24...31
wed.......4...11...18...25
thu.......5...12...19...26
fri.......6...13...20...27
sat.....[.7]..14...21...28
sun...1...8...15...22...29

Or correct is:
mon........2....9...16...23...30
tue........3...10...17...24...31
wed........4...11...18...25
thu........5...12...19...26
fri........6...13...20...27
sat......[.7]..14...21...28
sun...1....8...15...22...29
?????
I mean number of spaces.

Edited by author 03.03.2007 11:41
Re: Problem without problem statement!!!
Послано Fyodor Menshikov 3 мар 2007 23:13
I think you should not count space characters but rather use alignment like in sample.
Re: Problem without problem statement!!!
Послано MishaRash 21 июл 2015 22:27
The problem is that there is no information about this case in samples.