here is code of program!
var
      n, k : integer;

begin
   read(n, k);
   n := TRUNC(k*exp((n-1)*ln(k-1)));
   writeLn(n);
end.
if k = 10 and n = 3 then we can write that:
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
and 3 number maybe one of them.
first number maybe all of them,
second 9.
third 9 too,