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back to board for the range 1 to 2^31-1 even O(n) soln won't work i.e even a single loop will take more time if we want to use f(n,m) = abs(f(1,n)-f(1,m)) we need to store 2^31 values... how is it possible to store so many numbers!!!!
You don't need to store so many numbers. Tey to find another way (try to see how change length between fixed nodes). f(n,m) = abs(f(1,n) - f(1,m)) - it's ok. |
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