#include<stdio.h>
#include<math.h>
int main()
{
     double a[100000];
     signed long int i = 0;
     while (scanf("%lf", &a[i]) != EOF)
     {
         i++;
     }
     i--;
     while ( i >= 0)
     {
         printf("%.4lf\n",sqrt(a[i]));
         i--;
     }
     return ;
}

!!!!!EXTENDED for Pascal!!!!!!
!!!!!LONG DOUBLE for C++!!!!!!

try this:
double a [128*1024]

use dinamic memory try
double *a = (double *) malloc (sizeof(double)*128*1024);
and when you done before return
free (a);
thats all :)

Aleksa_Markoni, thank you!

Could you tell me why it should use dinamic memory ?
Thank you!

There is no need to use dinamic memory ...
Just make sure that your array is large enough.
But I wonder why the result I get is TLE ...
this is my code:
#include<stdio.h>
#include<string.h>
#include<math.h>

double a[100010];//make it larger and then I got AC

int main()
{
    int k=0;
    while(scanf("%lf",&a[k])!=EOF)k++;
    while(k)
        printf("%.4lf\n",sqrt(a[--k]));

    return 0;
}

Edited by author 21.10.2009 00:40

while your program submit
it replies Time limit exceeded
for what reason?