import java.io.*;
import java.util.*;

public class Main
{
       public static void main(String[] args) throws IOException
       {
          new Main().run();
       }

       StreamTokenizer in;
       PrintWriter out;

       void run() throws IOException
       {
          in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
          out = new PrintWriter(new OutputStreamWriter(System.out));
          solve();
          out.flush();
       }

       void solve() throws IOException
       {
          LinkedList<Double> myArr = new LinkedList<Double>();
          while(in.nextToken() != StreamTokenizer.TT_EOF)
          {
            myArr.add(Math.sqrt((double)(in.nval)));

          }
          myArr.add(0.0);
          ListIterator iterator = myArr.listIterator(myArr.size() - 1);
          while (iterator.hasPrevious())
      {
                out.printf("%.4f\n", iterator.previous());
      }
       }

}

I read the FAQS and other post but still cannot figure out whats the problem its working fine on my test cases which are as follows:

Description: First 4 are input numbers rest is output.

Test Case # 1:

2
5
3
5
2.2361
1.7321
2.2361
1.4142

Test Case # 2:

1427
0
876652098643267843
5276538
2297.0716
936297014.1164
0.0000
37.7757

Test Case # 3:

1 2 3 4
2.0000
1.7321
1.4142
1.0000

Test Case # 4:

2
            4
64
                                   49
7.0000
8.0000
2.0000
1.4142

Why am i getting the time limit exceed error ?

You can solve this problem on Java in two ways:

1. Use NumberFormat:

NumberFormat nf = NumberFormat.getInstance(Locale.US);
nf.setMaximumFractionDigits(6);
nf.setGroupingUsed(false);
out.println(nf.format(x));

You can get AC in 1.14 sec in such way

2. Use BigDecimal:

out.println(BigDecimal.valueOf(x).setScale(6, RoundingMode.HALF_UP));

You can get AC in 1.375 sec in such way