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| back to board | any hints? Posted by d3m0n1c  28 Oct 2011 04:36Re: any hints? Posted by Noob  29 Oct 2011 00:39Re: any hints? it's a cheat! =)Re: any hints? Posted by Noob  30 Oct 2011 02:08At least you should be able to write bruteforce in O(n^2 * 2^n) :)Re: any hints? Posted by aropan  31 Oct 2011 12:46For a pair of numbers the number of actions is equal to <length of the first number> + <length of the second number> - 2*<length of the longest common prefix> (numbers are treated as binary strings)READ !!!! Posted by Tuit  26 Nov 2011 15:44Bo`ladigan gap gapirgin-e!!!Re: any hints? Your must understand hint of 'aropan'. And get answer = 2^L*(L - 3*2^L + L*2^L + 3) P.S.: Mathcad can help you to find sum of such expression as FOR(z=0,..l)z*2^z. It's only math problem. P.P.S.: To find 2^L use http://en.wikipedia.org/wiki/Exponentiation_by_squaring Edited by author 22.05.2012 22:17Re: any hints? Posted by kostan3  19 Oct 2012 23:15чё это???? | 
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