Pleas Assist=)
#include <iostream>
#include <math.h>
#include <iomanip>
using namespace std;
int main()
{

double arr[32768];
int i=0;
double value=0;
while(cin>>value)
{
    if (value>0)
    {
        arr[i++]=sqrt(value);
        value=0;
    }
        else break;

}
cout<<setprecision(4)<<fixed;
while(i--)
{
    cout <<arr[i]<<endl;
}
system("pause");

}

Edited by author 15.09.2012 23:36

First of all the amount of numbers are about 129000 but not 32768 as you have written.

Right, but if you're using C++ why not use a dynamic container like std::vector.   If you don't know STL it's worth learning at least the STL containers.  vector, map, and set in particular are immensely useful and bring C++ up to "higher" level language status than C++ without them.   They're especially useful when you don't know the input limits beforehand because they grow automatically.

Edited by author 18.09.2012 13:41

#include<iostream>
#include<math.h>
using namespace std;
#pragma comment(linker, "/STACK:2000000")
void worc(){
   double k;
   if(scanf("%lf",&k)!=EOF){
     worc();
     printf("%.4lf\n",sqrt(k));
   }
}
int main()
{
   worc();
   return 0;
}