why wrong answer?



#include<stdio.h>
int main()
{float a,b,sum;
printf("a:");scanf("%f",&a);
printf("b:");scanf("%f",&b);
sum=a+b;
printf("a+b:%f",sum);
return 0;}

Even i got the wrong answer .
On a glance at your code if you give input as 1 and c ( letter ) you get a result 39 .which according to the problem statement is incorrect. It is concerned about addition of number so add test cases like checking whether input is valid for program .

Edited by author 01.04.2013 15:28

You mustn't print any prompts. For example: "a: " or "b: ". Also you only must make the sum of two INTEGER numbers. Is no necessary to use float, only use int.

+

http://acm.timus.ru/help.aspx?topic=judge&locale=en
Input data in the test cases always satisfy the constraints described in the problem statement. You don’t need to verify these constraints in your solutions.

No reason to wait input "1 c".

You have been already informed that no prompts allowed.

Another note - are you sure you can use "float" type?
In example (http://acm.timus.ru/help.aspx?topic=cpp) int is used instead. Float has less mantissa size - can be WA on big integers (big means "> 2^24").

Checked your solution locally and via online judge - answer for test is "6.000000", expected answer is 6, WA1.

Edited by author 16.02.2016 14:48