Please help me


#include <iostream>
#include <math.h>


using namespace std;

int main(int argc, const char * argv[])
{

    double stack[1000];

    int index = 0;
    while (cin >> stack[index]) {
        index++;
    }


    index--;
    for (; index > 0; index--) {
        printf("%.4lf\n", sqrt(stack[index]));
    }


}

There will be more than 1000 numbers.

double stack[1000]; - Your error is here

Use dynamic storage like stl vector

#include <stdio.h>
#include <math.h>
#include <vector>


using namespace std;

int main(int argc, const char * argv[])
{

    vector <double> stack;

    int index = 0;

    while (scanf("%lf", &stack[index++]) != EOF) {

    }

    for (index--; index > 0; index--) {
        printf("%.4lf\n", sqrt(stack[index]));
    }

}
still wrong answer, access violation. please help me

You cannot access stack[index] since its size is 0. Use an intermediary variable for the read number, and then use stack.push_back(x). Use stack.size() to retrieve the number of elements in the stack.
Or you can use a <list> instead of <vector>, and use push_front, so that in the end, you don't need to loop in reverse order.
Take a look on these STL containers, to get familiarized with them:
http://www.cplusplus.com/reference/vector/vector/push_back/
http://www.cplusplus.com/reference/list/list/push_front/

Edited by author 15.01.2014 17:11

Edited by author 15.01.2014 17:11