Discussion @ 1001. Reverse Root @ Timus Online Judge

Arderun Why wrong answer? Java [3] // Problem 1001. Reverse Root 19 Apr 2016 19:42

Sample numbers have different value of math.sqrt() in last digit. Why? This task is not so big level for hidden problem.

sample result:
2297.0716
936297014.1164
0.0000
37.7757

my result:
2297.0715
936297024.0000
0.0000
37.7757

import java.io.PrintWriter;
import java.util.Scanner;
import java.util.*;

public class AlgorithmTAsk {

    public static void main(String[] arg){

        Scanner in = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        ArrayList<Float> f = new ArrayList<Float>();

        while (in.hasNextLong()) {
            f.add((float) Math.sqrt(in.nextLong()));
        }

        for(int i = f.size()-1;i>=0;i--){
            out.printf("%8.6f\n",f.get(i));

        }

        out.flush();
    }
}

Edited by author 19.04.2016 19:45

ToadMonster Re: Why wrong answer? Java [2] // Problem 1001. Reverse Root 20 Apr 2016 00:19

Try double instead of float

Shiva S Dixith Help me out here [1] // Problem 1001. Reverse Root 24 Aug 2016 22:47

import java.util.Scanner;
import java.text.DecimalFormat;
import java.lang.StringBuffer;
import java.lang.Math;
public class Timus2{
    public static void main(String[] args){
        Scanner S = new Scanner(System.in);
        DecimalFormat df = new DecimalFormat("#.0000");
        StringBuffer result = new StringBuffer();
        while(S.hasNext()){
            result.append(df.format(Math.sqrt(S.nextDouble())) + "\n");
        }
        S.close();
        System.out.println(result);
    }
}

ToadMonster Re: Help me out here // Problem 1001. Reverse Root 25 Aug 2016 00:40

1) Any advantages of using "StringBuffer result"?
Is it really faster then just print result line by line?

2) Show here expected output, your program output, compare.

Discussion of Problem 1001. Reverse Root