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## Discussion of Problem 2002. Test Task

I hate the time limit
Posted by Savchuk Nickolay 12 Jun 2021 16:22
l1=[]
l2=[]
l3=[]
for i in range(0,1000):
l3.append(False)
def funct(a):
b=a.split()
if b[0]=='register':
if b[1] not in l1:
l1.append(b[1])
l2.append(b[2])
print("success: new user added")
else:
print("fail: user already exists")
if b[1] not in l1:
print("fail: no such user")
else:
k=l1.index(b[1])
if l3[k]:
print("fail: already logged in")
else:
if l2[k]==b[2]:
l3[k]=True
print("success: user logged in")
else:
elif b[0]=="logout":
k=l1.index(b[1])
if l3[k]:
l3[k]=False
print("success: user logged out")
else:
print("fail: already logged out")
f=int(input())
for m in range(0,f):
n=input()
funct(n)

f**king time limit!!!
Re: I hate the time limit
Posted by qumusabel 14 Jul 2021 17:34
List is O(n) lookup, while dict is O(log n), so use that