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Discussion of Problem 1226. esreveR redrO

I got an Accept and then was rejudged to a Wrong Answer
Posted by VladG 6 Nov 2002 11:44
I got an Accept and then after a day I got email that it was rejudge
and it is Wrong Answer. What this could mean???
It Minth that your program is Wrong
Posted by I am david. Tabo. 7 Nov 2002 09:04
Re: It Minth that your program is Wrong
Posted by VladG 7 Nov 2002 19:18
But, why. It performs exactly, what example says. Example of an
unclear case with "-" character.
It got Accept when I submitted it. Why I got email after a day that
it was rejudged and it is now a Wrong Solution.
It never happen to me before.

By the way, you can see my program it is in the next message of this
forum.

Thank you,
  Vladimir
Soo hepend with me. First i got AC but then WA.
Posted by I am david. Tabo. 9 Nov 2002 22:57
Var i,n,k,nn,bo:integer;
    s,s1,s2,s3:string;
    a:array [1..100] of string[255];
    q,q1:boolean;

begin
  q1:=true;
  repeat
    s:='';q:=false;bo:=1;s1:='';
    readln(s);inc (nn);n:=0;
    for i:=1 to length(s) do
      begin
        if not q1 then
          s1:='';
        if (s[i] in ['a'..'z']) or (s[i] in ['A'..'Z']) then
          begin
            inc (n);q1:=true;
            s1:=s1+s[i];q:=false;
          end
        else
          if ((s[i-1] in ['a'..'z']) or (s[i-1] in ['A'..'Z']))and
             ((s[i+1] in ['a'..'z']) or (s[i+1] in ['A'..'Z']))and
             (s[i]<>' ') then
            begin
              inc (n);q1:=true;
              s1:=s1+s[i];q:=false;
            end
          else
            begin
              if not q then
                for k:=n downto 1 do
                  begin
                    a[nn]:=a[nn]+s1[k];
                    q:=true;
                  end;
              a[nn]:=a[nn]+s[i];inc(n);
              q1:=false;bo:=n;n:=0;
            end;
      end;
  until (eof(input));
  bo:=length (s1);
  for k:=bo downto 1 do
    if (s1[k] in ['a'..'z']) or (s1[k] in ['A'..'Z']) then
      s2:=s2+s1[k]
    else
      s3:=s3+s1[k];
  a[nn]:=a[nn]+s2+s3;
  for i:=1 to nn do
    writeln (a[i]);
end.