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| back to board | It is 2 easy! Posted by kcm1700  20 May 2004 13:49isn`t it?
 Edited by author 20.05.2004 13:49
Re: It is 2 easy! YES it is But How to do it isn`t it?
 Edited by author 20.05.2004 13:49
Re: It is 2 easy! it seems easy but not too easyRe: It is 2 easy! Hi i wanto say that why my program gives error:here is my program:
 var
 k,n,x,y,z:longint;
 a:array[1..100000] of longint;
 b:array[1..100000] of longint;
 c:array[1..100000] of longint;
 begin
 readln(n);
 for k:=1 to n do
 readln(x,y);
 a[k]:=x;
 b[k]:=y;
 for k:=1 to n do
 begin
 c[k]:=((a[k]+b[k])+((a[k+1]+b[k+1]) div 10 ))mod 10;
 write(c[k]);
 end;
 end.
Re: It is 2 easy! Your algo is wrong for this task
 sehvdi ozde kokunnen.
Re: It is 2 easy! Posted by Linus  16 Aug 2006 01:31You forgot to write begin...end operators after entering values (for k:=1 to n do begin read(x, y) ...)
 Else your algoritm seems me not correct. :)
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