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Выгодное строительство дорог	MaxWonder		21 Jun 2014 17:50	1
Выгодное строительство дорог MaxWonder 21 Jun 2014 17:50 Привет, столкнулся с интересной задачкой, которую очень хочется решить правильно. Натолкните пожалуйста на мысль, о возможных алгоритмах для ее решения, спасибо. В двух соседних королевствах есть по N городов в каждом. Правители договорились соединить их N дорогами таким образом, чтобы между двумя городами из разных королевств была только одна дорога. Строительство дорог ведется совместными усилиями, но количество работников для строительства дороги между двумя городами может быть разной для каждого из королевств. При строительстве самой первой дороги, жребием определяется королевство, которое первое выбирает один из своих городов. Затем другое королевство выбирает один из своих городов и между ними строится дорога. Для строительства следующей дороги, право первым выбрать город, еще не соединенный никакой дорогой, переходит к королевству, которое выбирало город для предыдущей дороги во вторую очередь и так далее меняется очередность права первым выбрать город для очередной дороги, пока не будут построены все N дорог. Задачей каждого королевства, является трудоустройство большего числа работников, чем у соседнего королевства. Исходные данные: Количество городов в каждом из королевств: 2 <= N <= 10 Разница в количестве работников, необходимых для постройки дорог, между первым и вторым королевством: W[1..N, 1..N], где W[i, j] - это целое число от -255 до 255, разница в количестве работников между первым и вторым королевством, которые будут заняты при постройке дороги между i-м городом первого и j-м городом второго королевства. Каких алгоритмов необходимо придерживаться при ведении строительства дорог от лица первого королевства, если второе королевство также будет стараться использовать самый оптимальный алгоритм для своей победы при выборе городов? Пример: N = 2 W = {{ 2, 2 }, { -4, -2 }} Предположим, что второе королевство для первой дороги делает выбор первым и предлагает первый город, тогда нам как представителю первого королевства выгоднее соединить его дорогой с первым городом и трудоустроить на 2 работника больше. Тогда для второй дороги мы трудоустроим на 2 работника меньше и в результате будет ничья. Если мы для первой дороги выберем второй город первого королевства, то по результатам строительства двух дорог мы трудоустроим на 2 работника меньше и проиграем. Edited by author 21.06.2014 17:51
Why would this fail test 1	ElPsyCongroo	1220. Stacks	21 Jun 2014 12:19	1
Why would this fail test 1 ElPsyCongroo 21 Jun 2014 12:19 #include<vector> #include<stack> #include<iostream> int main() { int noOfInstructions = 0; std::cin>> noOfInstructions; std::vector< std::stack< int > > myVectorOfStacks; myVectorOfStacks.reserve( 1001 ); for( int inx = 0; inx < 1001; ++inx ) { myVectorOfStacks.push_back( std::stack<int>() ); } char instruction[3]; int stackNumber = 0; int stackValue = 0; for( int inx = 0; inx < noOfInstructions; ++inx ) { std::cin>> instruction; std::cin>> stackNumber; std::stack< int > & tempStack = myVectorOfStacks.at( stackNumber ); if( instruction[1] == 'U' ) { std::cin>> stackValue; tempStack.push( stackValue ); } else { std::cout<< tempStack.top()<< "\n"; tempStack.pop(); } } return 0; }
Why would this fail test 1	ElPsyCongroo	1220. Stacks	21 Jun 2014 12:14	1
Why would this fail test 1 ElPsyCongroo 21 Jun 2014 12:14 #include<vector> #include<stack> #include<iostream> int main() { int noOfInstructions = 0; std::cin>> noOfInstructions; std::vector< std::stack< int > > myVectorOfStacks; myVectorOfStacks.reserve( 1001 ); for( int inx = 0; inx < 1001; ++inx ) { myVectorOfStacks.push_back( std::stack<int>() ); } char instruction[3]; int stackNumber = 0; int stackValue = 0; for( int inx = 0; inx < noOfInstructions; ++inx ) { std::cin>> instruction; std::cin>> stackNumber; std::stack< int > & tempStack = myVectorOfStacks.at( stackNumber ); if( instruction[1] == 'U' ) { std::cin>> stackValue; tempStack.push( stackValue ); } else { std::cout<< tempStack.top()<< "\n"; tempStack.pop(); } } return 0; }
HELP!!! Time limit exceeded 0.531sec	Chukharev	1113. Jeep	21 Jun 2014 02:27	2
HELP!!! Time limit exceeded 0.531sec Chukharev 20 Jun 2014 21:33 PLZ HELP!!! why? #include<iostream> using namespace std; int main() { int a,m,n; double d,o,w; cin>>n>>m; a=0; w=0; o=0; bool q=true; while(q){ a++; d=m/(a << 1-1); if (w+d>=n){ q=false; } w=w+d; o=o+m; } d=n-w; o=o+d(a << 1-1); cout<<(abs(o+0.49999999999)); return 0; } Edited by author 21.06.2014 02:18* Edited by author 21.06.2014 02:18 Edited by author 21.06.2014 21:29 No subject Chukharev 21 Jun 2014 02:27 Edited by author 21.06.2014 21:27
No subject	Иван	1493. One Step from Happiness	21 Jun 2014 02:14	2
No subject Иван 21 Jun 2014 01:02 Edited by author 21.06.2014 02:14 No subject Иван 21 Jun 2014 02:14 Edited by author 21.06.2014 02:14
A simple solution using suffix arrays	McSweetsc	1590. Bacon’s Cipher	20 Jun 2014 20:54	3
A simple solution using suffix arrays McSweetsc 22 Apr 2011 00:07 Well, the N is rather small that we can construct the suffix array for O(N^2logN) for example, we get all the suffix and sort it: a aa aaa then calculate the longest common prefix(LCP) between two neighbour string we get : 1 2 it means that: the substring "a" occurs 3 times (in string 1,2, LCP is "a",in string 2,3, LCP is "aa", which also contains "a") , and should be counted as once the substring "aa" occurs twice and it's also should be counted as once then the answer should be : 3 * (3 + 1) / 2 - 1 - 2 = 3 Re: A simple solution using suffix arrays ASK 7 Feb 2014 00:15 https://sites.google.com/site/yuta256/sais is a good implementation of the suffix array Re: A simple solution using suffix arrays akos tajti 20 Jun 2014 20:54 i found the DC3 algorithm much easier to understand (and implement). and it is fast enough (even in scala)
Time limit on test #11	cra3y	1220. Stacks	20 Jun 2014 20:49	2
Time limit on test #11 cra3y 2 Dec 2013 23:15 i got 0.531 sec for this code #include <stdio.h> #include <stdlib.h> typedef unsigned int type; struct stack{ type* value; int cnt; int size; }; #define delta 4 #define getnum(num) do {\ (num) = 0; \ char c; \ while(1) { \ c = fgetc(stdin); \ if((c<'0')\|\|(c>'9')) break; \ (num)=10; \ (num)+=c-'0'; \ }\ }while(0) #define putnum(num) do { \ char str[16]; \ char it = &str[15];it = 0; \ if((num)==0) { fputc('0', stdout); } \ else { \ while(num) { \ --it; \ it = (char)((num)%10)+'0'; \ (num)/=10; \ } \ while(it) { \ fputc(it, stdout); \ ++it; \ } \ }\ fputc('\n', stdout); \ } while(0); struct stack st[1000] = {0}; int main() { int cnt; getnum(cnt); while(cnt--){ int id; char c,i; i=0; while((c = getchar())!=' ') ++i; getnum(id); --id; if(i>3) { st[id].cnt++; if(st[id].cnt > st[id].size) { st[id].size+=delta; st[id].value = (type)realloc(st[id].value, st[id].sizesizeof(type)); } getnum(st[id].value[st[id].cnt-1]); } else { st[id].cnt--; putnum(st[id].value[st[id].cnt]); if(st[id].cnt+delta<st[id].size) { st[id].size-=delta; st[id].value = (type)realloc(st[id].value, st[id].sizesizeof(type)); } } } return 0; } if set delta to 6, then i got MLE on test #12 =/ i broke my brain. Sorry for my English Re: Time limit on test #11 Иван 20 Jun 2014 20:49 у меня точно такой же алгоритм :) и точно такая же проблема :)
I'm stuck in test3, anyone could help me out by providing some tests, thanks	kezhenxu	1002. Phone Numbers	20 Jun 2014 19:13	1
I'm stuck in test3, anyone could help me out by providing some tests, thanks kezhenxu 20 Jun 2014 19:13 Are there any tricks in test3??? Please provide me with some tests! thanks Edited by author 20.06.2014 19:18
test 2	mdcoroiu	1002. Phone Numbers	20 Jun 2014 18:44	9
test 2 mdcoroiu 6 May 2010 15:18 what is wrong with my solution? Re: test 2 mdcoroiu 6 May 2010 15:38 can anyone tell me what's feature of test 2 test 2 mdcoroiu 6 May 2010 16:55 I not understanding. Result of Test 1 is ok, but Test 2 wrong. What particularity contains Test 2? Re: test 2 Лукьянчиков Владимир Игоревич 6 May 2010 17:44 timustests.lx.ro - you can find tests here Re: test 2 grebenyuksv 20 Apr 2011 16:03 which exactly is the second one? --------------------------- 72953994777284856983298465189367895127892382885672377321235444325988737612787346332 1495 wkd wkdw kdw wkdww kdww dww wkdwwg kdwwg dwwg wwg wkdwwgp kdwwgp dwwgp wwgp wgp wkdwwgpp kdwwgpp dwwgpp wwgpp wgpp gpp wkdwwgppp kdwwgppp dwwgppp wwgppp wgppp gppp ppp wkdwwgpppa kdwwgpppa dwwgpppa wwgpppa wgpppa gpppa pppa ppa wkdwwgpppat kdwwgpppat dwwgpppat wwgpppat wgpppat gpppat pppat ppat pat wkdwwgpppatg kdwwgpppatg dwwgpppatg wwgpppatg wgpppatg gpppatg pppatg ppatg patg atg wkdwwgpppatgt kdwwgpppatgt dwwgpppatgt wwgpppatgt wgpppatgt gpppatgt pppatgt ppatgt patgt atgt tgt wkdwwgpppatgtk kdwwgpppatgtk dwwgpppatgtk wwgpppatgtk wgpppatgtk gpppatgtk pppatgtk ppatgtk patgtk atgtk tgtk gtk wkdwwgpppatgtkm kdwwgpppatgtkm dwwgpppatgtkm wwgpppatgtkm wgpppatgtkm gpppatgtkm pppatgtkm ppatgtkm patgtkm 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ggdakwttpdpmiaptpdgmd gdakwttpdpmiaptpdgmd dakwttpdpmiaptpdgmd akwttpdpmiaptpdgmd kwttpdpmiaptpdgmd wttpdpmiaptpdgmd ttpdpmiaptpdgmd tpdpmiaptpdgmd pdpmiaptpdgmd dpmiaptpdgmd pmiaptpdgmd miaptpdgmd iaptpdgmd aptpdgmd ptpdgmd tpdgmd pdgmd dgmd gmd adtattkmpadppdaiadkgggdakwttpdpmiaptpdgmdd dtattkmpadppdaiadkgggdakwttpdpmiaptpdgmdd tattkmpadppdaiadkgggdakwttpdpmiaptpdgmdd attkmpadppdaiadkgggdakwttpdpmiaptpdgmdd ttkmpadppdaiadkgggdakwttpdpmiaptpdgmdd tkmpadppdaiadkgggdakwttpdpmiaptpdgmdd kmpadppdaiadkgggdakwttpdpmiaptpdgmdd mpadppdaiadkgggdakwttpdpmiaptpdgmdd padppdaiadkgggdakwttpdpmiaptpdgmdd adppdaiadkgggdakwttpdpmiaptpdgmdd dppdaiadkgggdakwttpdpmiaptpdgmdd ppdaiadkgggdakwttpdpmiaptpdgmdd pdaiadkgggdakwttpdpmiaptpdgmdd daiadkgggdakwttpdpmiaptpdgmdd aiadkgggdakwttpdpmiaptpdgmdd iadkgggdakwttpdpmiaptpdgmdd adkgggdakwttpdpmiaptpdgmdd dkgggdakwttpdpmiaptpdgmdd kgggdakwttpdpmiaptpdgmdd gggdakwttpdpmiaptpdgmdd ggdakwttpdpmiaptpdgmdd gdakwttpdpmiaptpdgmdd dakwttpdpmiaptpdgmdd akwttpdpmiaptpdgmdd kwttpdpmiaptpdgmdd wttpdpmiaptpdgmdd ttpdpmiaptpdgmdd tpdpmiaptpdgmdd pdpmiaptpdgmdd dpmiaptpdgmdd pmiaptpdgmdd miaptpdgmdd iaptpdgmdd aptpdgmdd ptpdgmdd tpdgmdd pdgmdd dgmdd gmdd mdd adtattkmpadppdaiadkgggdakwttpdpmiaptpdgmdda dtattkmpadppdaiadkgggdakwttpdpmiaptpdgmdda tattkmpadppdaiadkgggdakwttpdpmiaptpdgmdda attkmpadppdaiadkgggdakwttpdpmiaptpdgmdda ttkmpadppdaiadkgggdakwttpdpmiaptpdgmdda tkmpadppdaiadkgggdakwttpdpmiaptpdgmdda kmpadppdaiadkgggdakwttpdpmiaptpdgmdda mpadppdaiadkgggdakwttpdpmiaptpdgmdda padppdaiadkgggdakwttpdpmiaptpdgmdda adppdaiadkgggdakwttpdpmiaptpdgmdda dppdaiadkgggdakwttpdpmiaptpdgmdda ppdaiadkgggdakwttpdpmiaptpdgmdda pdaiadkgggdakwttpdpmiaptpdgmdda daiadkgggdakwttpdpmiaptpdgmdda aiadkgggdakwttpdpmiaptpdgmdda iadkgggdakwttpdpmiaptpdgmdda adkgggdakwttpdpmiaptpdgmdda dkgggdakwttpdpmiaptpdgmdda kgggdakwttpdpmiaptpdgmdda gggdakwttpdpmiaptpdgmdda ggdakwttpdpmiaptpdgmdda gdakwttpdpmiaptpdgmdda dakwttpdpmiaptpdgmdda akwttpdpmiaptpdgmdda kwttpdpmiaptpdgmdda wttpdpmiaptpdgmdda ttpdpmiaptpdgmdda tpdpmiaptpdgmdda pdpmiaptpdgmdda dpmiaptpdgmdda pmiaptpdgmdda miaptpdgmdda iaptpdgmdda aptpdgmdda ptpdgmdda tpdgmdda pdgmdda dgmdda gmdda mdda dda pa -1 pa wkdwwgpppatgtkmwtdawtgmkitwdmptwkia ptw adtattkmpadppdaiadkgggdakwttpdpmiaptpdgmdda - given in the sample pa wkdwwgpppatgtkmwtdawtgmkitwdmptwkiapt wadtattkmpadppdaiadkgg gdakwttpdpmiaptpdgmdda - that's what my program outputs -------------------------------- 2111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 4 bj bjj jj jjjj -1 bjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj - both the sample and my program give ------------------------------------------------------- 2285064252258215 5 long false cat tail black -1 cat long black tail - the answers match as well. -------------------------------------------------- is the mismatch in the first one really a mistake? Both answers consist of 4 words. Please help. Edited by author 20.04.2011 16:06 Edited by author 20.04.2011 16:06 Re: test 2 Anatoly 23 Feb 2012 02:53 grebenyuksv, your 1st test contains digit '6' in the word. but input words can contain letters only. Re: test 2 shifei 25 Sep 2013 08:24 not only '6', but also a ' ' and a '$'. Here's the input for anyone who want to have a test. ----------------------------- 2285064252258215 5 long false cat tail black 2111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 4 bj bjj jj jjjj 72953994777284856983298465189367895127892382885672377321235444325988737612787346332 1495 wkd wkdw kdw wkdww kdww dww wkdwwg kdwwg dwwg wwg wkdwwgp kdwwgp dwwgp wwgp wgp wkdwwgpp kdwwgpp dwwgpp wwgpp wgpp gpp wkdwwgppp kdwwgppp dwwgppp wwgppp wgppp gppp ppp wkdwwgpppa kdwwgpppa dwwgpppa wwgpppa wgpppa gpppa pppa ppa wkdwwgpppat kdwwgpppat dwwgpppat wwgpppat wgpppat gpppat pppat ppat pat wkdwwgpppatg kdwwgpppatg dwwgpppatg wwgpppatg wgpppatg gpppatg pppatg ppatg patg atg wkdwwgpppatgt kdwwgpppatgt dwwgpppatgt wwgpppatgt wgpppatgt gpppatgt pppatgt ppatgt patgt atgt tgt wkdwwgpppatgtk kdwwgpppatgtk dwwgpppatgtk wwgpppatgtk wgpppatgtk gpppatgtk pppatgtk ppatgtk patgtk atgtk tgtk gtk wkdwwgpppatgtkm kdwwgpppatgtkm dwwgpppatgtkm wwgpppatgtkm wgpppatgtkm gpppatgtkm pppatgtkm ppatgtkm patgtkm atgtkm tgtkm gtkm tkm wkdwwgpppatgtkmw kdwwgpppatgtkmw dwwgpppatgtkmw wwgpppatgtkmw wgpppatgtkmw gpppatgtkmw pppatgtkmw ppatgtkmw patgtkmw atgtkmw tgtkmw gtkmw tkmw kmw wkdwwgpppatgtkmwt kdwwgpppatgtkmwt dwwgpppatgtkmwt wwgpppatgtkmwt wgpppatgtkmwt gpppatgtkmwt pppatgtkmwt ppatgtkmwt patgtkmwt atgtkmwt tgtkmwt gtkmwt tkmwt kmwt mwt wkdwwgpppatgtkmwtd kdwwgpppatgtkmwtd dwwgpppatgtkmwtd wwgpppatgtkmwtd wgpppatgtkmwtd gpppatgtkmwtd pppatgtkmwtd ppatgtkmwtd patgtkmwtd atgtkmwtd tgtkmwtd gtkmwtd tkmwtd kmwtd mwtd wtd wkdwwgpppatgtkmwtda kdwwgpppatgtkmwtda dwwgpppatgtkmwtda wwgpppatgtkmwtda wgpppatgtkmwtda gpppatgtkmwtda pppatgtkmwtda ppatgtkmwtda patgtkmwtda atgtkmwtda tgtkmwtda gtkmwtda tkmwtda kmwtda mwtda wtda tda wkdwwgpppatgtkmwtdaw kdwwgpppatgtkmwtdaw dwwgpppatgtkmwtdaw wwgpppatgtkmwtdaw wgpppatgtkmwtdaw gpppatgtkmwtdaw pppatgtkmwtdaw ppatgtkmwtdaw patgtkmwtdaw atgtkmwtdaw tgtkmwtdaw gtkmwtdaw tkmwtdaw kmwtdaw mwtdaw wtdaw tdaw daw wkdwwgpppatgtkmwtdawt kdwwgpppatgtkmwtdawt dwwgpppatgtkmwtdawt wwgpppatgtkmwtdawt wgpppatgtkmwtdawt gpppatgtkmwtdawt pppatgtkmwtdawt ppatgtkmwtdawt patgtkmwtdawt atgtkmwtdawt tgtkmwtdawt gtkmwtdawt tkmwtdawt kmwtdawt mwtdawt wtdawt tdawt dawt awt wkdwwgpppatgtkmwtdawtg kdwwgpppatgtkmwtdawtg dwwgpppatgtkmwtdawtg wwgpppatgtkmwtdawtg wgpppatgtkmwtdawtg gpppatgtkmwtdawtg pppatgtkmwtdawtg ppatgtkmwtdawtg patgtkmwtdawtg atgtkmwtdawtg tgtkmwtdawtg gtkmwtdawtg tkmwtdawtg kmwtdawtg mwtdawtg wtdawtg tdawtg dawtg awtg wtg wkdwwgpppatgtkmwtdawtgm kdwwgpppatgtkmwtdawtgm dwwgpppatgtkmwtdawtgm wwgpppatgtkmwtdawtgm wgpppatgtkmwtdawtgm gpppatgtkmwtdawtgm pppatgtkmwtdawtgm ppatgtkmwtdawtgm patgtkmwtdawtgm atgtkmwtdawtgm tgtkmwtdawtgm gtkmwtdawtgm tkmwtdawtgm kmwtdawtgm mwtdawtgm wtdawtgm tdawtgm dawtgm awtgm wtgm tgm wkdwwgpppatgtkmwtdawtgmk kdwwgpppatgtkmwtdawtgmk dwwgpppatgtkmwtdawtgmk wwgpppatgtkmwtdawtgmk wgpppatgtkmwtdawtgmk gpppatgtkmwtdawtgmk pppatgtkmwtdawtgmk ppatgtkmwtdawtgmk patgtkmwtdawtgmk atgtkmwtdawtgmk tgtkmwtdawtgmk gtkmwtdawtgmk tkmwtdawtgmk kmwtdawtgmk mwtdawtgmk wtdawtgmk tdawtgmk dawtgmk awtgmk wtgmk tgmk gmk wkdwwgpppatgtkmwtdawtgmki kdwwgpppatgtkmwtdawtgmki dwwgpppatgtkmwtdawtgmki wwgpppatgtkmwtdawtgmki wgpppatgtkmwtdawtgmki gpppatgtkmwtdawtgmki pppatgtkmwtdawtgmki ppatgtkmwtdawtgmki patgtkmwtdawtgmki atgtkmwtdawtgmki tgtkmwtdawtgmki gtkmwtdawtgmki tkmwtdawtgmki kmwtdawtgmki mwtdawtgmki wtdawtgmki tdawtgmki dawtgmki awtgmki wtgmki tgmki gmki mki wkdwwgpppatgtkmwtdawtgmkit kdwwgpppatgtkmwtdawtgmkit dwwgpppatgtkmwtdawtgmkit wwgpppatgtkmwtdawtgmkit wgpppatgtkmwtdawtgmkit gpppatgtkmwtdawtgmkit pppatgtkmwtdawtgmkit ppatgtkmwtdawtgmkit patgtkmwtdawtgmkit atgtkmwtdawtgmkit tgtkmwtdawtgmkit gtkmwtdawtgmkit tkmwtdawtgmkit kmwtdawtgmkit mwtdawtgmkit wtdawtgmkit tdawtgmkit dawtgmkit awtgmkit wtgmkit tgmkit gmkit mkit kit wkdwwgpppatgtkmwtdawtgmkitw kdwwgpppatgtkmwtdawtgmkitw dwwgpppatgtkmwtdawtgmkitw wwgpppatgtkmwtdawtgmkitw wgpppatgtkmwtdawtgmkitw gpppatgtkmwtdawtgmkitw pppatgtkmwtdawtgmkitw ppatgtkmwtdawtgmkitw patgtkmwtdawtgmkitw atgtkmwtdawtgmkitw tgtkmwtdawtgmkitw gtkmwtdawtgmkitw tkmwtdawtgmkitw kmwtdawtgmkitw mwtdawtgmkitw wtdawtgmkitw tdawtgmkitw dawtgmkitw awtgmkitw wtgmkitw tgmkitw gmkitw mkitw kitw itw wkdwwgpppatgtkmwtdawtgmkitwd kdwwgpppatgtkmwtdawtgmkitwd dwwgpppatgtkmwtdawtgmkitwd wwgpppatgtkmwtdawtgmkitwd wgpppatgtkmwtdawtgmkitwd gpppatgtkmwtdawtgmkitwd pppatgtkmwtdawtgmkitwd ppatgtkmwtdawtgmkitwd patgtkmwtdawtgmkitwd atgtkmwtdawtgmkitwd tgtkmwtdawtgmkitwd gtkmwtdawtgmkitwd tkmwtdawtgmkitwd kmwtdawtgmkitwd mwtdawtgmkitwd wtdawtgmkitwd tdawtgmkitwd dawtgmkitwd awtgmkitwd wtgmkitwd tgmkitwd gmkitwd mkitwd kitwd itwd twd wkdwwgpppatgtkmwtdawtgmkitwdm kdwwgpppatgtkmwtdawtgmkitwdm dwwgpppatgtkmwtdawtgmkitwdm wwgpppatgtkmwtdawtgmkitwdm wgpppatgtkmwtdawtgmkitwdm gpppatgtkmwtdawtgmkitwdm pppatgtkmwtdawtgmkitwdm ppatgtkmwtdawtgmkitwdm patgtkmwtdawtgmkitwdm atgtkmwtdawtgmkitwdm tgtkmwtdawtgmkitwdm gtkmwtdawtgmkitwdm tkmwtdawtgmkitwdm kmwtdawtgmkitwdm mwtdawtgmiitwdm wtdawtgmkitwdm tdawtgmkitwdm dawtgmkitwdm awtgmkitwdm wtgmkitwdm tgmkitwdm gmkitwdm mkitwdm kitwdm itwdm twdm wdm wkdwwgpppatgtkmwtdawtgmkitwdmp kdwwgpppatgtkmwtdawtgmkitwdmp dwwgpppatgtkmwtdawtgmkitwdmp wwgpppatgtkmwtdawtgmkitwdmp wgpppatgtkmwtdawtgmkitwdmp gpppatgtkmwtdawtgmkitwdmp pppatgtkmwtdawtgmkitwdmp ppatgtkmwtdawtgmkitwdmp patgtkmwtdawtgmkitwdmp atgtkmwtdawtgmkitwdmp tgtkmwtdawtgmkitwdmp gtkmwtdawtgmkitwdmp tkmwtdawtgmkitwdmp kmwtdawtgmkitwdmp mwtdawtgmkitwdmp wtdawtgmkitwdmp tdawtgmkitwdmp dawtgmkitwdmp awtgmkitwdmp wtgmkitwdmp tgmkitwdmp gmkitwdmp mkitwdmp kitwdmp itwdmp gdakwttpdpmiaptpdgmdda twdmp wdmp dmp wkdwwgpppatgtkmwtdawtgmkitwdmpt kdwwgpppatgtkmwtdawtgmkitwdmpt dwwgpppatgtkmwtdawtgmkitwdmpt wwgpppatgtkmwtdawtgmkitwdmpt wgpppatgtkmwtdawtgmkitwdmpt gpppatgtkmwtdawtgmkitwdmpt pppatgtkmwtdawtgmkitwdmpt ppatgtkmwtdawtgmkitwdmpt patgtkmwtdawtgmkitwdmpt atgtkmwtdawtgmkitwdmpt tgtkmwtdawtgmkitwdmpt gtkmwtdawtgmkitwdmpt tkmwtdawtgmkitwdmpt kmwtdawtgmkitwdmpt mwtdawtgmkitwdmpt wtdawtgmkitwdmpt tdawtgmkitwdmpt dawtgmkitwdmpt awtgmkitwdmpt wtgmkitwdmpt tgmkitwdmpt gmkitwdmpt mkitwdmpt kitwdmpt itwdmpt twdmpt wdmpt dmpt mpt wkdwwgpppatgtkmwtdawtgmkitwdmptw kdwwgpppatgtkmwtdawtgmkitwdmptw dwwgpppatgtkmwtdawtgmkitwdmptw wwgpppatgtkmwtdawtgmkitwdmptw wgpppatgtkmwtdawtgmkitwdmptw gpppatgtkmwtdawtgmkitwdmptw pppatgtkmwtdawtgmkitwdmptw ppatgtkmwtdawtgmkitwdmptw patgtkmwtdawtgmkitwdmptw atgtkmwtdawtgmkitwdmptw tgtkmwtdawtgmkitwdmptw gtkmwtdawtgmkitwdmptw tkmwtdawtgmkitwdmptw kmwtdawtgmkitwdmptw mwtdawtgmkitwdmptw wtdawtgmkitwdmptw tdawtgmkitwdmptw dawtgmkitwdmptw awtgmkitwdmptw wtgmkitwdmptw tgmkitwdmptw gmkitwdmptw mkitwdmptw kitwdmptw itwdmptw twdmptw wdmptw dmptw mptw ptw wkdwwgpppatgtkmwtdawtgmkitwdmptwk kdwwgpppatgtkmwtdawtgmkitwdmptwk dwwgpppatgtkmwtdawtgmkitwdmptwk wwgpppatgtkmwtdawtgmkitwdmptwk wgpppatgtkmwtdawtgmkitwdmptwk gpppatgtkmwtdawtgmkitwdmptwk pppatgtkmwtdawtgmkitwdmptwk ppatgtkmwtdawtgmkitwdmptwk patgtkmwtdawtgmkitwdmptwk atgtkmwtdawtgmkitwdmptwk tgtkmwtdawtgmkitwdmptwk gtkmwtdawtgmkitwdmptwk tkmwtdawtgmkitwdmptwk kmwtdawtgmkitwdmptwk mwtdawtgmkitwdmptwk wtdawtgmkitwdmptwk tdawtgmkitwdmptwk dawtgmkitwdmptwk awtgmkitwdmptwk wtgmkitwdmptwk tgmkitwdmptwk gmkitwdmptwk mkitwdmptwk kitwdmptwk itwdmptwk twdmptwk wdmptwk dmptwk mptwk ptwk twk wkdwwgpppatgtkmwtdawtgmkitwdmptwki kdwwgpppatgtkmwtdawtgmkitwdmptwki dwwgpppatgtkmwtdawtgmkitwdmptwki wwgpppatgtkmwtdawtgmkitwdmptwki wgpppatgtkmwtdawtgmkitwdmptwki gpppatgtkmwtdawtgmkitwdmptwki pppatgtkmwtdawtgmkitwdmptwki ppatgtkmwtdawtgmkitwdmptwki patgtkmwtdawtgmkitwdmptwki atgtkmwtdawtgmkitwdmptwki tgtkmwtdawtgmkitwdmptwki gtkmwtdawtgmkitwdmptwki tkmwtdawtgmkitwdmptwki kmwtdawtgmkitwdmptwki mwtdawtgmkitwdmptwki wtdawtgmkitwdmptwki tdawtgmkitwdmptwki dawtgmkitwdmptwki awtgmkitwdmptwki wtgmkitwdmptwki tgmkitwdmptwki gmkitwdmptwki mkitwdmptwki kitwdmptwki itwdmptwki twdmptwki wdmptwki dmptwki mptwki ptwki twki wki wkdwwgpppatgtkmwtdawtgmkitwdmptwkia kdwwgpppatgtkmwtdawtgmkitwdmptwkia dwwgpppatgtkmwtdawtgmkitwdmptwkia wwgpppatgtkmwtdawtgmkitwdmptwkia wgpppatgtkmwtdawtgmkitwdmptwkia gpppatgtkmwtdawtgmkitwdmptwkia pppatgtkmwtdawtgmkitwdmptwkia ppatgtkmwtdawtgmkitwdmptwkia patgtkmwtdawtgmkitwdmptwkia atgtkmwtdawtgmkitwdmptwkia tgtkmwtdawtgmkitwdmptwkia gtkmwtdawtgmkitwdmptwkia tkmwtdawtgmkitwdmptwkia kmwtdawtgmkitwdmptwkia mwtdawtgmkitwdmptwkia wtdawtgmkitwdmptwkia tdawtgmkitwdmptwkia dawtgmkitwdmptwkia awtgmkitwdmptwkia wtgmkitwdmptwkia tgmkitwdmptwkia gmkitwdmptwkia mkitwdmptwkia kitwdmptwkia wkdwwgpppatgtkmwtdawtgmkitwdmptwkiapt itwdmptwkia twdmptwkia wdmptwkia dmptwkia mptwkia ptwkia twkia wkia kia wkdwwgpppatgtkmwtdawtgmkitwdmptwkiap kdwwgpppatgtkmwtdawtgmkitwdmptwkiap dwwgpppatgtkmwtdawtgmkitwdmptwkiap wwgpppatgtkmwtdawtgmkitwdmptwkiap wgpppatgtkmwtdawtgmkitwdmptwkiap gpppatgtkmwtdawtgmkitwdmptwkiap pppatgtkmwtdawtgmkitwdmptwkiap ppatgtkmwtdawtgmkitwdmptwkiap patgtkmwtdawtgmkitwdmptwkiap 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gdakwttpdpmiaptpdgmdda dakwttpdpmiaptpdgmdda akwttpdpmiaptpdgmdda kwttpdpmiaptpdgmdda wttpdpmiaptpdgmdda ttpdpmiaptpdgmdda tpdpmiaptpdgmdda pdpmiaptpdgmdda dpmiaptpdgmdda pmiaptpdgmdda miaptpdgmdda iaptpdgmdda aptpdgmdda ptpdgmdda tpdgmdda pdgmdda dgmdda gmdda mdda dda pa -1 --------------------- the answer could be : cat long black tail bjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj jjjj pa wkdwwgpppatgtkmwtdawtgmkitwdmptwkiapt wadtattkmpadppdaiadkgg gdakwttpdpmiaptpdgmdda --------------------- Good luck! Edited by author 25.09.2013 08:25 Re: test 2 kezhenxu 20 Jun 2014 18:44 I've passed this test but still wa!! -_-!! Re: test 2 A-shot 1 Dec 2011 19:05 In my case, WA#2 was printing "No solution" instead of "No solution."
variation --> possible a new problem	Doctor Lai	2000. Grand Theft Array V	20 Jun 2014 10:31	2
variation --> possible a new problem Doctor Lai 19 May 2014 19:32 I was trying to solve this and I kinda mis-understood in the first place, which makes the problem hard to solve. If the player can decide on the first move (just the first move), then it would be much more complex. For example, 5 1 2 3 4 5 3 3 The current answer is 12 3 because the first player takes 3, 4, 5 and the second player takes 0 2 1 However, if we allow players to skip their first pick, in other words, (move and pick) instead of (pick and move). So there are few more possibilities. if first player picks 3, then the second player can pick 4 and 5 ==> 6, 9 if the first player picks 4, then the second player can pick 3, 2 and 1 ==> 9, 6 maybe I think too much ? :) Re: variation --> possible a new problem Nguyen Trung Hieu 20 Jun 2014 10:31 You helped me to solve this problem. But the result in this test case is 12, 3. :D Edited by author 20.06.2014 10:31
WA3 and incorrect statement	Wasdek	1863. Peaceful Atom	19 Jun 2014 12:38	2
WA3 and incorrect statement Wasdek 22 Jan 2014 20:38 My program get WA3, but work right on my tests. I can't find a mistake. Please, give me some tests. Also, why 0<=s<=n and n>0 ? Is it incorrect statement? Re: WA3 and incorrect statement ErikR 19 Jun 2014 12:38 For WA3, check how you initialize the global min and max depth. n > 0 is fine. n cannot be zero, but s can be.
Pay attention to the situation that n=1,or you maybe WA on test#2	WYKay	1005. Stone Pile	19 Jun 2014 06:44	2
Pay attention to the situation that n=1,or you maybe WA on test#2 WYKay 15 Jun 2009 16:31 ~ Re: Pay attention to the situation that n=1,or you maybe WA on test#2 gaxxx 19 Jun 2014 06:44 it works!
Why WA 2 ?	Milovanov Maxim	1821. Biathlon	18 Jun 2014 18:52	13
Why WA 2 ? Milovanov Maxim 19 Mar 2011 15:50 Give me test 2 Re: Why WA 2 ? MOPDOBOPOT (USU) 19 Mar 2011 17:33 3 Masha 91:0.0 Sasha 90:0.0 Vasya 3:0.0 ans: 1 Vasya Edited by author 20.03.2011 12:37 Re: Why WA 2 ? Milovanov Maxim 19 Mar 2011 17:39 Thank Re: Why WA 2 ? Amrodis 19 Mar 2011 18:11 Edited by author 22.03.2011 02:51 Re: Why WA 2 ? daftcoder [Yaroslavl SU] 19 Mar 2011 18:40 Bot not only Vasya? My AC program says 1 Vasya == BTW check test 5 E 1:20.0 D 1:10.0 C 0:30.0 B 0:20.0 A 0.10.0 Ans should be 4 A B C E Re: Why WA 2 ? Amrodis 19 Mar 2011 19:02 My solution also says 1 Vasia and for the BTW check test the same answer. but i have wa 4. please give me some other examples. thanks. Re: Why WA 2 ? MOPDOBOPOT (USU) 20 Mar 2011 12:39 I'm sorry, of course the answer will be 1 Vasya Re: Why WA 2 ? Atmo [ONU] 27 Jul 2011 20:46 To daftcoder [Yaroslavl SU]: Your test has a mistake in the last line. It should be like this: 5 E 1:20.0 D 1:10.0 C 0:30.0 B 0:20.0 A 0:10.0 Edited by author 27.07.2011 20:48 Re: Why WA 2 ? [TDUweAI] daminus 1 Mar 2012 22:22 MOPDOBOPOT (USU) wrote 19 March 2011 17:33 3 Masha 91:0.0 Sasha 90:0.0 Vasya 3:0.0 ans: 1 Vasya Edited by author 20.03.2011 12:37 It is not TRUE!!!!!!!!!!!!!!!!!! Re: Why WA 2 ? ramon93i7 24 Aug 2012 20:28 It's obviously true. Re: Why WA 2 ? Furkhat 20 Nov 2012 11:56 Re: Why WA 2 ? Furkhat 20 Nov 2012 12:04 Edited by author 20.11.2012 12:16 Re: Why WA 2 ? Andros 18 Jun 2014 18:52 MOPDOBOPOT (USU) wrote 19 March 2011 17:33 3 Masha 91:0.0 Sasha 90:0.0 Vasya 3:0.0 But in the statement it says it's in MM:SS.D format, so shouldn't it be 91:00.0, 03:00.0, etc.?
WA #17 why?	Иван	1777. Anindilyakwa	17 Jun 2014 19:06	1
WA #17 why? Иван 17 Jun 2014 19:06 #include <stdio.h> #include <stdlib.h> #include <unistd.h> #define True 1 #define False 0 #define N 15 #define MAX_DIFF 1000000000000000001 void print_a(unsigned long long a[N]) { int i; printf("\n----------------\n"); for (i = 0; a[i] != 0; i++) { printf("%llu\n", a[i]); } printf("\n--------------\n"); } void sort(unsigned long long a[N]) { int i, j, s_fl; unsigned long long tmp; for (i = 0, s_fl = True; s_fl == True; i++) { for (j = 0, s_fl = False; j < N-i-1; j++) { if (a[j] < a[j + 1]) { s_fl = True; tmp = a[j]; a[j] = a[j + 1]; a[j + 1] = tmp; } } } } int main(int argc, char *argv[]) { int i, j, c; unsigned long long prev, diff; unsigned long long max[N] = {0}; for (i = 0; i < 3; i++) scanf("%llu", &max[i]); sort(max); for (j = 2, c = 0; max[j] != 0; j++, c++) { for (i = 0, diff = MAX_DIFF; max[i + 1] != 0; i++) { prev = max[i] - max[i + 1]; if (prev < diff) diff = prev; } max[j + 1] = diff; sort(max); // print_a(max); } printf("%d\n", c); return 0; }
scala too slow?	Vassili Skarine	2011. Long Statement	17 Jun 2014 14:20	3
scala too slow? Vassili Skarine 31 Mar 2014 08:21 tried tons of optimizations but Scala solution still TLE, any suggestions? Re: scala too slow? Vassili Skarine 31 Mar 2014 08:45 ok so I got AC the key difference seems to be in using correct way to read the input if I use readLine().split(' ').map(_.toInt) then it always TLE but if I read input using Java Scanner: val sc = new Scanner(System.in); .... sc.nextInt() ... then it works fine Edited by author 31.03.2014 08:45 Re: scala too slow? akos tajti 17 Jun 2014 14:20 I also have many problems with scala. My scala code runs two times slow than the corresponding java code. Sometimes it's really hard to optimize. My tips (in general, not specifically about this problem): * don't use vars if not really necessary * foldLeft and similar functions are slow unfortunately (although I tend to use them anyways, only switch to for when I got a TLE) * array initialization is REALLY slow especially if you use fill (much more slower than java). try to keep your arrays as small as possible. For example sometimes it's possible to keep only the last two rows of a matrix.
this is very good and short code	Sunnat	1567. SMS-spam	17 Jun 2014 12:09	2
this is very good and short code Sunnat 16 Jan 2012 02:34 #include<cstdio> int main() { int s=0,a; for(;(a=getchar())!='\n';(a==' ')?s++:(a%3==0)?s+=3:s+=a%3); printf("%i",s); return 0; } Re: this is very good and short code Ильдар(TUIT Urgench) 17 Jun 2014 12:09 Why it's work?
Runtime error (access violation) on test 13	Nekto89	1203. Scientific Conference	17 Jun 2014 02:24	1
Runtime error (access violation) on test 13 Nekto89 17 Jun 2014 02:24 Hi. What's in stdin of 13th test? My solution is crashing with std::cin or scanf. With VS 2010 scanf_s it doesn't crash. UPD hm... replaced scanf with std::cin that I was using at first. Looks like it has nothing to do with it, but because of compiler... UPD2 comparator function for std::sort requires strict ordering :( Edited by author 17.06.2014 02:44
c++ code always wrong in test #3, anyone who get accepted could help me?	WENXIANG LU	1209. 1, 10, 100, 1000...	17 Jun 2014 00:22	3
c++ code always wrong in test #3, anyone who get accepted could help me? WENXIANG LU 8 Nov 2013 22:07 #include <iostream> #include <cmath> bool isOne (long n) { double intPart; double para = (1 + sqrt ( 8 * n -7)) / 2; double fractPart = modf(para, &intPart); if (fractPart == 0.0) return true; else return false; } int main() { using namespace std; long value; long num, i = 0; cin >> num; while (i < num) { cin >> value; if (isOne (value)) cout << "1 "; else cout << "0 "; i++; } return 0; } Re: c++ code always wrong in test #3, anyone who get accepted could help me? junior 9 Dec 2013 08:12 Think about how big can be 8 * n. Re: c++ code always wrong in test #3, anyone who get accepted could help me? Ильдар(TUIT Urgench) 17 Jun 2014 00:22 accepted if you use long long instead long
Did anyone get AC with O(n4) algo after redjudgement 15 Sep 2013	sanok	1004. Sightseeing Trip	16 Jun 2014 14:10	1
Did anyone get AC with O(n4) algo after redjudgement 15 Sep 2013 sanok 16 Jun 2014 14:10 I implemented the first idea came to my mind: for each connected vertices v1,v2 removing edge v1-v2 and finding shortest paths from v1 to v2 with Dijkstra. As for my estimations it should be O(edges^2) or O(vertices^4) for very connected graphs. It was reported in other threads of this discussion that this solution should fit time limits, but mine does not pass test #3 (time limit exceed). I am curious if solutions like mine now can be accepted. Did anyone have success with that approach after rejudgement in Sep 2013? Or now only O(v^3) solutions can pass all tests? Thanks
There can be such situation?	Vitalik	1347. Blog	16 Jun 2014 09:14	4
There can be such situation? Vitalik 4 Jul 2006 13:14 Help!!! I have WA#17!!! 1 a <blog> <friend>x<friend>b<friend>c</friend></friend></friend> </blog> Thanks beforehand Re: There can be such situation? Alex Fetisov 9 Aug 2006 14:12 My AC prog gives that result: a 1: c, x 2: 3: Re: There can be such situation? svr 4 Aug 2007 11:53 Such data don't precence in tests. My Ac program gives absolutely another answer. Friends decription <friend>x<friend>b<friend>c</friend></friend></friend> incorrect because for main corresponding pair <friend>- </friend> we have wrong name :x<friend>b<friend>c</friend></friend> (contains simbols differ from latin letters and _) In blog decription there are nothing about enclosed friend's tags. If we refuse wrong names answer must be: a 1: c 2: 3: Re: There can be such situation? Adhambek 16 Jun 2014 09:14 This is incorrect test case.

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