I too did not know what was wrong with my solution, but got accepted when replaced:

for (int i = n; i >= 1; i--)
    if (time[i] < time[besti]) besti = i;

with:

for (int i = n; i >= 1; i--)
    if (time[i] + epsilon < time[besti]) besti = i;

With epsilon = 1e-9.
Good luck! :)

always wa at test 11,why?

Why 15 ?

Edited by author 10.08.2014 12:35

Edited by author 10.08.2014 12:35

When? :)

why i always got wrong 3 ?

You can solve that with algo Djikstra.
We have 6!*8*8 vertex (hash of cube and point) .
And all vertexs have <=4 edges.
P.s. sry for English )

Edited by author 09.08.2014 16:51

import java.util.List;
import java.util.ArrayList;
import java.util.Scanner;


public class Spion {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        List<String>shifr = new ArrayList();
        String word = in.next();

    shifr.add(""+word.charAt(0));

    for(int i =1;i<word.length();i++){
        String s =""+word.charAt(i);
        shifr.add(s);

        if(shifr.get(shifr.lastIndexOf(s)).equals(shifr.get(shifr.indexOf(s))) && shifr.lastIndexOf(s)==shifr.indexOf(s)+1)
            {
            shifr.remove(shifr.get(shifr.lastIndexOf(s)));
            shifr.remove(shifr.get(shifr.indexOf(s)));

            };

    }

        for(String n: shifr){

            System.out.print(n);
        }







    }

}

what's wrong?

Can you please give me some tests?

Тест №2 противоречит условию задачи , это тест такой :
1
1 0
(подобрал с помощью бинпоиска)

import java.util.Scanner;

public class AcmTimusRu {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int a = s.nextInt();
        int b = s.nextInt();

          if (39 + 2 * a > a + 2 * b) {
            System.out.println(2*a+39);
        } else {
            System.out.println(2*b+40);
        }
    }
}

import java.text.DecimalFormat;
import java.util.Scanner;

public class prob {

    public static void main(String[] args) {
        Scanner c = new Scanner(System.in);
        DecimalFormat twoDecimals = new DecimalFormat("0.00%");
      int n = c.nextInt();
      int counter = 0;
      double m = c.nextInt();
      int []a = new int [c.nextInt()];
      for(int i = 0; i < a.length; i++){
          a[i]= c.nextInt();
      }
      for(int j = 1; j<=n; j++){
          int z = j;
          for (int i = 0; i < a.length; i++){
              if(a[i] == z)
                  counter++;
          }
          System.out.println(counter*100 / m);
      }
    }
}

parsing in just one line XD

from string import *
from functools import *

[[a1,b1],[a2,b2],[a3,b3]] = map(partial(map,int),map(split,map(raw_input, [""]*3)))

& in py3k:
from functools import *
[[a1,b1],[a2,b2],[a3,b3]] = map(partial(map,int),map(lambda x:x.split(),map(input, [""]*3)))

Edited by author 05.04.2014 04:37

I can't understand why my program work slow, I don't know any algorithm that can solvе this problem in beter time. My program solve it in 0.125s, when others in 0.031. Why ? Please help me :)

9 15
1 2
3 1
1 5
4 2
6 2
3 4
3 6
4 5
6 5
5 7
6 7
6 8
8 7
7 9
8 9
1 9

Ans: 0

Many AC codes input the n=100, output have many zero before the radix point, the relative error is not enough very much! Why did they accept?