import java.util.Scanner;
public class ObratniyKoren {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub


        int i;
        int n;
        Scanner scan=new Scanner(System.in);
        n=scan.nextInt();
        long []a=new long[n];
        for(i=1; i<n; i++)
        {
            a[ i]=scan.nextInt();
        }
        System.out.println("выводим массив наоборот");
for(i=n-1; i>0; i--)
{
    System.out.println((double)Math.sqrt(a[i]));

    }
    }

}

Find the solution and explanation of this task in
manyprogrammingtutorials.blogspot.com

#include <iostream>
#include <math.h>
using namespace std;

double len_points(double x1, double x2, double y1, double y2)
{
    return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
}

int main()
{
    const double pi = 3.14159;
    double sum = 0, arr[101][2], r;
    int n;

    cin>>n>>r;
    for(int i = 0; i < n; ++i)
        cin>>arr[i][0]>>arr[i][1];

    for(int i = 0; i < (n - 1); ++i)
        sum += len_points(arr[i][0], arr[i + 1][0], arr[i][1], arr[i + 1][1]);

    sum += len_points(arr[0][0], arr[n - 1][0], arr[0][1], arr[n - 1][1]) + 2 * pi * r;
    printf("%.2lf", sum);

    return 0;
}

I wrote a e-mail to timus_support@acm.timus.ru about incompleteness of statements of some problems (1089 and 1934) and created posts in respective problems
threads quite a while ago but didn't get any kind of feedback.
Bugs in statements are still here.

Does it mean letter were lost or someting?

Edited by author 04.10.2014 22:40

I always WA at TEST9,who can give me a test like test9 ? other test in discuss were all used.It's right.

What is the format of output, blank spaces before number?

I have wa8 when I used float numbers, when I changed it to double I get ac.

import java.util.Scanner;
public class Summa {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
Scanner scan=new Scanner( System.in);
System.out.println("Введите значение a");
int a;
a=scan.nextInt();
System.out.println("Введите значение b");
int b;
b=scan.nextInt();

System.out.println(" a + b = " + (a + b));

    }

}

I don't understand what's wrong? In my IDEA all works!

import java.io.IOException;
import java.util.Scanner;


public class summa {
    public static void main(String[] args) throws IOException {
        Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        int[] mas = new int[n*n];
        if(n!= 0) {
            for (int i = 0; i < n * n; i++) {
                mas[i]=s.nextInt();
            }
            if(mas.length>1) {
                qSort(mas, 0, mas.length-1);
                for (int i = 0; i < mas.length; i++) {
                    System.out.print(mas[i] + " ");
                }
            }else System.out.println(mas[0]);
        }else System.out.println("0 элемнтов");
    }

    public static void qSort(int[] A, int low, int high) {
        int i = low;
        int j = high;
        int x = A[(low+high)/2];
        do {
            while(A[i] < x) ++i;
            while(A[j] > x) --j;
            if(i <= j){
                int temp = A[i];
                A[i] = A[j];
                A[j] = temp;
                i ++ ; j --;
            }
        } while(i <= j);

        if(low < j) qSort(A, low, j);
        if(i < high) qSort(A, i, high);
    }
}

Edited by author 02.10.2014 20:36

Edited by author 02.10.2014 20:36

Any suggestions of the test? I rewrote solution from numerical to purely geometric, but still WA #10 and I can't find the reason.

Can anyone provide with more tests? especially Test#3 ?

It's not the easiest problem and I don't know good solution, but if I was on the olympiad and would have to solve the problem, I would just precalculate the answer.

Why "Time limit exceeded" ???

Edited by author 28.09.2014 09:03

Use G++ 4.7.2. G++ 4.7.2 C11 works wrong.

import java.util.Scanner;
public class Acm {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        int[] a = new int[n];
        int[] b = new int[n];
        for(int j = 0; j < n; j++){
                Scanner u = new Scanner(System.in);
                   a[j] = s.nextInt();
            b[j] = s.nextInt();
        }

        for(int p = 100; p >= 0; p--){
            for(int q = 0; q < n; q++){
                if(b[q] == p){
                    System.out.println(a[q] + " " + b[q]);
                }
            }
        }
    }
}

Edited by author 26.09.2014 23:34

hi,i know! there are some solution in this discussion that is a dangerous thing for someone that want to think more... so i say something about this problem for only hint..

for solving this problem this is better to check 2 or 3 example then consider a general case with n as input then try to simulate the answer and in the final step code it.

be successful...

I tried everything before I realized that my program should accept numbers like 1.e+1 even if there is no digits after '.'. Weird! I hope this information would be helpful to someone.

first the person goes to (2,2) from (1,1) +141 then (3,2) +100 so why not 241?

My algorithm is
1. sort wait time min -> max
2. variable time declared to add total time
3. add minimal wait time and exam time to var(time)
4. add exam time everybody
5. if time > freetime print time-freetime
   else print 0
I think my algorithm is right ,but I got WA #7
Could you help me plz?