Why does this string of code cause "Compilation error":
vector<vector<string>>* middleresult;
?

I my MSVS compiler it goes well. But not here... :(
Tnx for any help.

#include <iostream>
#include <math.h>
using namespace std;

int main()
{

long b=-1,c;
long A[10000];

while(cin>>c)
{
    b=b+1;
    A[b-1]=c;
}

for(int i=b-1;i>=0;i--)
{
    printf(".4ld\n",sqrt(double(A[i])));
}


return 0;
}

Edited by author 25.07.2007 20:00

What is the output for this two inputs??

3 2
1 2


and

3 2
1 2 2

#include <stdio.h>
#include <math.h>
void main()
{
    double n;
    while(scanf("%lf",&n) != EOF)
        printf("%.4lf\n",sqrt(n));
}
It gets WA on the 1st test, although it should work (in theory). The problem is that I can't check whether it reads as it should just because I don't know how to put EOF symbol at the end of the input manually. Does anyone know how it should be done?

Edited by author 09.07.2007 20:30

my AC program for these test
4
zzz*2#
*3*4#
*2#
www#

gives output
zzz

it's wrong
correct output is
#

att

Edited by author 20.09.2006 14:31

The first one got AC but the second one got WA.
I have initialized every char in ans to be ' '.

OH, I see...
I should let ans[80] to be '\0'...
sorry..~

Edited by author 23.07.2007 21:58

The equality holds when the sum of i-th digits of numbers A and B (A[i]+B[i]<=9)
Using this write a simple program. It will be a TL program but...
try running it for k=1,2,3,4,5,6,7 and you should notice a rule how the answer for k+1 is formed.

And one more thing. You should use long arithmetics. For k=50 answer has 87 digits.

Good luck.

Can one word appear only at most once or more times?

#include <stdio.h>
#include <math.h>

long int n, k, hour;
double x, y;
int main(void)
{
   scanf("%ld%ld", &n, &k);
   if (n == 1)
   {
      printf("0\n");
      return 0;
   }
   n--;
   x = floor(log(k)/log(2)) + 1;
   y = pow(2, x) - 1;
   n -= y;
   hour = x;
   hour += n / k;
   if (n % k != 0)
       hour++;
   printf("%ld\n", hour);
   return 0;
}

What the fucking test.
I test this program on sophisticated tests but
vsio katu pod xvost.
:-P

New tests were added. 275 authors lost AC.

what finish the flow of the entering?
since there are absent "." or "0" at the end of the entering

For example program must work some:
4 <INPUT
0000 <INPUT
0000 >OUTPUT
011  <INPUT
0110 >OUTPUT
1011 <INPUT
1001 >OUTPUT
11011<INPUT
1111 >OUTPUT

using EOF allways in INPUT

Condition of problem says that
"Two planets have stuck each other if they have at least one common point"
But sample #1 show that it must be
"Two planets have stuck each other if they have at least two common points" .
I used this fact and got AC.
Please, correct this.



Edited by author 15.07.2007 01:56

program ural_1012;
 var
  a1,a0,p:longint;
  n,k,i:integer;
 begin
  readln(n,k);
  a1:=k-1;
  for i:=2 to n do
   begin
    p:=a1;
    a1:=(a1+a0)*(k-1);
    a0:=p;
   end;
   writeln(a1+a0);
 end.

Look at this test:

2
0
0

My accepted program outputs "0-1" when the right answer is "00".

i implement sweep line algorithm, using  STL set

Please try my program for different input data, I don't know where I am wrong. Maybe I missunderstood problem, everyone use array, I don't think it's necessary ?!

#include <iostream.h>
#include <math.h>

int main()
{
      int niz[10];
      int brojac = 1;
      int rezultat;
      int p = 1;
      int koren;
      for (int i = 0; i < 10; i++)
          cin >> niz[i];
      for (int j = 0; j < 10; j++)
          p = p * niz[j];
      if (p == 1)
      {
         cout <<1;
         return 0;
      }
      koren = floor(sqrt((double)p));

      for (int k = 2; k <=koren; k++)
      {
          if (p % k == 0)
          {
             if (p/k == k)
                brojac++;
             else
                 brojac = brojac + 2;
          }
      }
      brojac++;

          rezultat = brojac % 10;
          cout << rezultat;

      return 0;
}

Please, post some tests...