who can tell me,what's the sixth datas. why always WA in test 6

what is test 9

# include <stdio.h>
# include <conio.h>
# include <math.h>
# include <stdlib.h>
# include <time.h>
# include <limits.h>

bubble( int a[] , int n )
{
        int i , j , t;

        for( i = n - 1 ; i >= 1 ; i-- )
             for( j = 1 ; j <= i ; j++ )
                  if( a[j - 1] > a[j] ){
                      t = a[j - 1];
                      a[j - 1] = a[j];
                      a[j] = t;
                  }
}

int bul_( int *dizi , int optimum , int adet )
{
      static int min = INT_MAX;
      int i;
      min = min < optimum ? min : optimum ;
      if( dizi[0] > optimum )
          return;
      if( adet == 0 && dizi[0] < optimum )
          min = min < optimum - dizi[0] ? min : optimum - dizi[0] ;
      for( i = 0 ; i < adet ; ++i )
           bul_( dizi + i + 1 , optimum - dizi[0] , adet - i - 1 );

      return min;
}

int main()
{
      int dizi[100] , adet , i , optimum , toplam = 0 , deger;
      scanf("%i",&adet);
      for( i = 0 ; i < adet ; ++i ){
           scanf("%i",&dizi[i]);
           toplam += dizi[i];
      }
      bubble( dizi , adet );

      optimum = toplam / 2;
      deger = bul_( dizi , optimum , adet );
      printf("%i",toplam % 2 == 0 ? deger * 2 : 2 * deger + 1 );
      system("pause");
      return 0;
}


this code solve only four test case

1) Read the problem properly (I misread 256 KB to be 256 Bytes)
2) 256KB = 256 * 1024 Bytes
3) How many numbers can be used in 256KB of data (and how much space is used storing them)

Try this:
2
1 1 1
1 1 1
Answer:
1 1
1 1
Good luck!

my be it's no hard problem. Why few men solved?

After lot of submit AC!! It's no hard, but tricky problem for me:))

I didn't use epsilon!!!

Edited by author 22.08.2012 19:49

Please, give some useful tests.

В условии написано, что домино перевёрнута.
Но я отыслал перевёрнутая версия - ошибка,  а не перевёрнутая версия принита, что за задача?

Edited by author 21.08.2012 15:51

Edited by author 21.08.2012 16:22

plz some body explain with details plz.

Edited by author 20.08.2012 17:09

Edited by author 20.08.2012 17:09

#include <iostream>

using namespace std;

int main()
{
    int a[101];
    int k;
    cin>>k;
    for (int i=0; i<k; i++)
    {
        cin>>a[i];
    }
    for (int i=0; i<k; i++)
    {
        int q=i;
        int min=a[i];
        for (int j=i+1; j<k; j++ )
            if (a[j]<a[i])
            {
                q=j;
                min=a[j];
            }
        if (q!=i)
        {
            int tmp=a[i];
            a[i]=a[q];
            a[q]=tmp;
        }
    }
    long long s=0;
    for (int i=0; i<=(k/2); i++)
        s=s+((a[i]/2)+1);
    cout<<s<<endl;
    return 0;
}

plz explain what this test no shows ?

type t=record
     x:real;
     y:real;
     end;
function arccos(a:real):real;
var t:real;
Begin
if a=1 then arccos:=0
else if a=-1 then arccos:=180 else begin
t:=a/sqrt(1-sqr(a));
arccos:=180*((pi/2)-arcTan(t))/pi;
end;
end;


function dlina(x1,y1,x2,y2:real): real;
begin
 dlina:=sqrt( (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2) );
end;

function cos_(x1,y1,x2,y2,x3,y3:real):real;
begin

cos_:=( dlina(x3,y3,x2,y2)*dlina(x3,y3,x2,y2) +
 dlina(x1,y1,x2,y2)*dlina(x1,y1,x2,y2) -
 dlina(x1,y1,x3,y3)*dlina(x1,y1,x3,y3)  ) /
 2*dlina(x1,y1,x2,y2)*dlina(x3,y3,x2,y2);

end;
var n,i:integer; x,y,p,cos,r:real; mas:array[1..102] of t;
Begin
readln(n,r);
p:=0;
for i:=1 to n do begin
  readln(mas[i].x,mas[i].y);
  if i>1 then p:=p+dlina(mas[i-1].x,mas[i-1].y,mas[i].x,mas[i].y);
end;

p:=p+dlina(mas[1].x,mas[1].y,mas[n].x,mas[n].y);

mas[n+1]:=mas[1]; mas[n+2]:=mas[2];

for i:=1 to n do begin
 cos:=-cos_(mas[i].x,mas[i].y,mas[i+1].x,mas[i+1].y,mas[i+2].x,mas[i+2].y);
 p:=p+arccos(cos)*2*pi*r/360;
end;

writeln(p:1:2);
end.

Edited by author 21.03.2011 01:38

What's there?

Please give me tests!

Edited by author 18.08.2012 19:36