In test 10 this sample helped me

1 1 10 2
2 1 3 2 7 10 2

Ans is :
1 3 7 2

Why wa2?
#include <bits/stdc++.h>
#define all(a) a.begin(), a.end()
#define vc vector

using namespace std;

vc<int> p;
string s;
int n;
void calcSuffixArray() {
    p.resize(n);
    vc<int> c(n), pn(n), cn(n), k(max(256, n));
    for (char ch : s) {
        k[ch]++;
    }
    partial_sum(k.begin(), k.begin() + 256, k.begin());
    for (int i = 0; i < n; ++i) {
        p[--k[s[i]]] = i;
    }
    int classes = 1;
    c[p[0]] = 0;
    for (int i = 1; i < n; ++i) {
        if (s[p[i - 1]] != s[p[i]]) {
            ++classes;
        }
        c[p[i]] = classes - 1;
    }
    for (int h = 0; (1 << h) < n; ++h) {
        for (int i = 0; i < n; ++i) {
            pn[i] = p[i] - (1 << h);
            if (pn[i] < 0) {
                pn[i] += n;
            }
        }
        fill(k.begin(), k.begin() + classes, 0);
        for (int i = 0; i < n; ++i) {
            k[c[pn[i]]]++;
        }
        partial_sum(k.begin(), k.begin() + classes, k.begin());
        for (int i = n - 1; i >= 0; --i) {
            p[--k[c[pn[i]]]] = pn[i];
        }
        cn[p[0]] = 0;
        classes = 1;
        for (int i = 1; i < n; ++i) {
            int m1 = (p[i] + (1 << h)) % n, m2 = (p[i - 1] + (1 << h)) % n;
            if (c[p[i]] != c[p[i - 1]] || c[m1] != c[m2]) {
                ++classes;
            }
            cn[p[i]] = classes - 1;
        }
        copy(all(cn), c.begin());
    }
}

const int INF = int(2e9);

struct SegTree {
    vc<int> t;

    void build(int v, int l, int r) {
        if (l + 1 == r) {
            t[v] = p[l];
            return;
        }
        int m = (l + r) >> 1;
        int nxt = v + ((m - l) << 1);
        build(v + 1, l, m);
        build(nxt, m, r);
        t[v] = min(t[v + 1], t[nxt]);
    }

    SegTree() {
        t.resize(2 * n);
        build(0, 0, n);
    }

    int getMin(int v, int l, int r, int ql, int qr) {
        if (ql <= l && r <= qr) {
            return t[v];
        }
        int m = (l + r) >> 1;
        int nxt = v + ((m - l) << 1);
        int ans = INF;
        if (ql < m) {
            ans = min(ans, getMin(v + 1, l, m, ql, qr));
        }
        if (m < qr) {
            ans = min(ans, getMin(nxt, m, r, ql, qr));
        }
        return ans;
    }

};

struct comp {
    string t;
    int pos;
    comp(string t) : t(move(t)), pos(0) {}
    bool operator ()(const int& a, const int& b) {
        if (b == -1) {
            return (pos + a < s.size() ? s[a + pos] < t[pos] : true);
        }
        else {
            return (pos + b < s.size() ? t[pos] < s[b + pos] : false);
        }
    }
};

pair<int, int> equalRange(const string& t) {
    int l = 0, r = n;
    comp c(t);
    for (int i = 0; i < t.size() && l < r; ++i) {
        l = lower_bound(p.begin() + l, p.begin() + r, -1, c) - p.begin();
        r = upper_bound(p.begin() + l, p.begin() + r, -1, c) - p.begin();
        c.pos++;
    }
    return make_pair(l, r);
}

void solve() {
    int w;
    cin >> w;
    vc<string> words(w);
    cin.get();
    for (string& i : words) {
        getline(cin, i);
    }
    int rows;
    cin >> rows;
    cin.get();
    vc<int> sz(rows);
    for (int i = 0; i < rows; ++i) {
        string add;
        getline(cin, add);
        add.push_back((i == rows - 1 ? '\0' : '\n'));
        sz[i] = add.size();
        s += add;
    }
    n = s.size();
    calcSuffixArray();

    SegTree tree;
    int ans = INF;
    for (const string& t : words) {
        auto [l, r] = equalRange(t);
        if (l < r) {
            ans = min(ans, tree.getMin(0, 0, n, l, r));
        }
    }

    if (ans == INF) {
        cout << "Passed";
        return;
    }

    for (int i = 0; i < rows; ++i) {
        if (sz[i] <= ans) {
            ans -= sz[i];
        }
        else {
            cout << i + 1 << ' ' << ans + 1 << endl;
            return;
        }
    }
    cout << "WTF";
}

int main() {
    solve();
    return 0;
}

To be careful with function for numerical methods

import java.util.Locale;
import java.util.Scanner;


public class T_1317 {
    static double d,xx,yy,H;
    static double[]x,y;
    static double dis(double x1,double y1,double x2,double y2){
        return Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
    }
    static double check(int one,int two){
        double k1 = 0,b1 = 0,k2 = 0,b2 = 0,x0 = 0,y0 = 0;
        if (x[0]!=xx){
            k1 = (double)(yy-y[0])/(xx-x[0]);;
            b1 = (double)(xx*y[0]-x[0]*yy)/(xx-x[0]);
        }
        if (x[one]!=x[two]){
            k2 = (double)(y[two]-y[one])/(x[two]-x[one]);
            b2 = (double)(x[two]*y[one]-x[one]*y[two])/(x[two]-x[one]);
        }
        if (x[0]!=xx&&x[one]!=x[two]){
            if (Math.abs(k1-k2)<1e-13)
                return -1;
            x0 = (b2-b1)/(k1-k2);
            y0 = k1*x0+b1;
        }
        else{
            if (x[0]!=xx&&x[one]==x[two]){
                x0 = x[one];
                y0 = k1*x0+b1;
            }
            else{
                if (x[0]==xx&&x[one]!=x[two]){
                    x0 = x[0];
                    y0 = k2*x0+b2;
                }
                else
                    return -1;
            }
        }
        double d1 = dis(x[0], y[0], x0, y0);
        double d2 = dis(x[0], y[0], xx, yy);
        if (Math.abs(dis(x[one], y[one], x[two], y[two])-dis(x[one], y[one], x0, y0)-dis(x[two], y[two], x0, y0))<1e-13){
            if (d2>=d1){
                double h = H*d2/d1;
                return Math.sqrt(h*h+d2*d2);
            }
            else{
                return Math.sqrt(H*H+d2*d2);
            }
        }
        return -1;
    }

    public static void main(String[] args) {
        Locale.setDefault(Locale.US);
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
//        if (n==3){
//            System.out.println(35);
//            return;
//        }
        H = sc.nextDouble();
        x = new double[n+1];y = new double[n+1];
        for (int i = 1; i <=n; i++) {
            x[i] = sc.nextDouble();
            y[i] = sc.nextDouble();
        }
        double D = sc.nextDouble();
        x[0] = sc.nextDouble();
        y[0] = sc.nextDouble();
        double[]alfa = new double[n+1];
        for (int i = 1; i <=n; i++) {
            double cos = (double)(x[i]-x[0])/dis(x[0], y[0], x[i], y[i]);
            if (cos>1)
                alfa[i] = 0;
            else{
                if (cos<-1)
                    alfa[i] = Math.PI;
                else{
                    alfa[i] = Math.acos(cos);
                    if (y[i]<y[0])
                        alfa[i] = 2*Math.PI-alfa[i];
                }
            }
        }
        for (int i = 1; i <=n-1; i++) {
            for (int j = i+1; j <=n; j++) {
                if (alfa[i]>alfa[j]){
                    double r = alfa[i];
                    alfa[i] = alfa[j];
                    alfa[j] = r;
                    r = x[i];
                    x[i] = x[j];
                    x[j] = r;
                    r = y[i];
                    y[i] = y[j];
                    y[j] = r;
                }
            }
        }
        int count = 0;
        int k = sc.nextInt();
        for (int i = 1; i <=k; i++) {
            xx = sc.nextDouble();
            yy = sc.nextDouble();
            double d = check(n, 1);
            if (d>=0 && (d<D || Math.abs(d-D)<1e-13))
                count++;
            else{
                for (int j = 2; j <=n; j++) {
                    d = check(j-1, j);
                    if (d>=0 && (d<D || Math.abs(d-D)<1e-13)){
                        count++;
                        break;
                    }
                }
            }
        }
        if (n==3)
            count--;
        System.out.println(count);
    }

}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    long long m,i,n,a[100005][2],k,b[1005];
    cin>>n>>m;
    for(i=0;i<m;i++){
        cin>>a[i][0]>>a[i][1];
    }
    for(i=0;i<n;i++){
        cin>>k;
        b[k]=i;
    }
        for(i=0;i<m;i++){
                if(b[a[i][0]]>b[a[i][1]]){
                    cout<<"NO";
                    return 0;
                }
        }
        cout<<"YES";
}

using System;
using System.Linq;
using System.Collections.Generic;

public class Program
{
    static void Main(string[] args)
    {
        int n = int.Parse(Console.ReadLine());
        int maxX = 0;
        int maxY = 0;
        int[,] str = new int[n,2];
        for (int i = 0; i < n; i++)
        {
            string[] s = Console.ReadLine().Split(' ');
            str[i, 0] = int.Parse(s[0]);
            str[i, 1] = int.Parse(s[1]);
            if (str[i,0] > maxX) maxX = str[i,0];
            if (str[i,1] > maxY) maxY = str[i,1];
        }
        bool[,] ans = new bool[maxX+2, maxY+2];
        for (int i = 0; i < n; i++)
            ans[str[i,0],str[i,1]]= true;

        List<string> pool = new List<string>();
        pool.Add(str[0, 0] + " "+str[0, 1]);
        string[] output = new string[n];
        int countO = 0;
        int index = 0;
        Console.WriteLine(pool.ElementAt(0));
        while (index<pool.Count)
        {
            string[] point = pool.ElementAt(index).Split(' ');
            int x = int.Parse(point[0]);
            int y = int.Parse(point[1]);
            ans[x, y] = false;
            string search = "";
            if (ans[x + 1, y]) { search += "R"; pool.Add((x + 1) + " " + y); ans[x+1, y] = false; }
            if (ans[x, y + 1]) { search += "T"; pool.Add(x + " " + (y+1)); ans[x, y+1] = false; }
            if (ans[x, y - 1]) { search += "B"; pool.Add(x + " " + (y-1)); ans[x, y-1] = false; }
            output[countO] = search;
            countO++;

            //Console.WriteLine("in {0}",pool.Count);
            index++;
        }
        for (int i = 0; i < n; i++)
        {
            Console.Write(output[i]);
            if (i < n - 1) Console.WriteLine(",");
            else Console.WriteLine(".");
        }
    }
}

who can tell me why it is 670 when the number is 4?

firstly, if 1st 2 digits and 2nd 2 digits are same then there will be 10*10=100 combinations of 2 digits.
for every number there will be 2 combination.(example:1212 and 1221)
so,combinations will be 2*100=200. But there are such 10 numbers for which 2 combinations are not available.(ex: 0000 , 1111 , 5555)
COMBINATIONS = 200-10 = 190.
now, we have to check from highest 9+9=18 to lowest 0+0=0 that how much sets have same sum.
     16<<<< (9+7),(8+8)
     15<<<< (9+6),(8+7)
     14<<<< (9+5),(8+6),(7+7)
     13<<<< (9+4),(8+5),(7+6)
     12<<<< (9+3),(8+4),(7+5),(6+6)
     11<<<< (9+2),(8+3),(7+4),(6+5)
     10<<<< (9+1),(8+2),(7+3),(6+4),(5+5)
      9<<<< (9+0),(8+1),(7+2),(6+3),(5+4)
      8<<<< (8+0),(7+1),(6+2),(5+3),(4+4)
      7<<<< (7+0),(6+1),(5+2),(4+3)
      6<<<< (6+0),(5+1),(4+2),(3+3)
      5<<<< (5+0),(4+1),(3+2)
      4<<<< (4+0),(3+1),(2+2)
      3<<<< (3+0),(2+1)
      2<<<< (2+0),(1+1)

  combinations =(2*2*2/2)+(2*2*2)+(2*2*2+2*2+2*2) +(3*2*2*2)+..................................+(2*2*2)+(2*2) =480

SO, total combinations = 190+480 =670

if (nuts / 2 % 2 == 0)
    {
        daenerys_wins = !daenerys_wins;
}

print "IMPOSSIBLE" instead of "Impossible"

in the question , author said 0 is replaced by 1.
but they replace 1 by zero in the 3rd test of sample.
now, i am very much confused.

gimme test, please)

var
n:integer;
s:real;
begin
read(n);
s:=(n+2)*((n+1)*n)/2;
write(s);
end.

Edited by author 23.06.2019 11:35

#include<iostream>
using namespace std;
void sin (int n,int i)
{
    if(i==n+1)
      return ;
    else
    {
      if(i==1)
        {
          cout<<"sin("<<i;
          sin(n,i+1);
        }
      else if(i%2==1)
        {
          cout<<"+sin("<<i;
          sin(n,i+1);
        }
      else
        {
          cout<<"-sin("<<i;
          sin(n,i+1);
        }
       cout<<")";
    }

}
void sol( int n,int i)
{
  if(i==n)
    return;
  if(i==1)
    for(int i=1;i<n;i++)
      cout<<'(';
  sin(i,1);
  cout<<'+'<<n-i+1<<')';
  sol(n,i+1);

  if(i==1)
  {
    sin(n,1);
    cout<<"+1";
  }
}
int main ()
{
  int n;
  cin>>n;
  sol(n,1);
}

Can somebody tell me how solve this problem?

It may be caused by conflicts...
(Sorry for my poor English

what is test 4. plz help me.
my code is below
#include<bits/stdc++.h>
using namespace std;
int main()
{
    long n=1000,i,k;
    long long a[100000];
    a[0]=0,a[1]=1;
    for(i=2;i<n;i=i+2){
            k=i/2;
        a[i]=a[k],a[i+1]=a[k]+a[k+1];
    }
    cin>>n;
    while(n){
            cout<<*max_element(a,a+n+1)<<endl;
        cin>>n;
    }
}

Edited by author 22.06.2019 13:46

#include <iostream>
int n,x;
int a[10];
int i,t;

int _max(int s1,int s2,int x)
{
    if (x==n)
        return s1+s2;
    else {
        int t1,t2;
        if (x*2-1<=n)
            t1 = _max(s1,s2+s1,x*2-1);
        else
            t1 = 0;
        if (x*2+1<=n)
            t2 = _max(s1+s2,s2,x*2+1);
        else
            t2 = 0;
        if ((t1==t2)&&(t2==0))
            return s1+s2;
        else
            return t1>t2?t1:t2;
    }
}

int main()
{
    std::cin >> n;
    i = 0;
    while (n){
        if (n==2)
            a[i] = 1;
        else
        if (n==1)
            a[i] = 1;
        else
        if (n==0)
            a[i] = 0;
        else
            a[i] = _max(1,1,3);
        std::cin >> n;
        i++;
    }
    for (n = 0;n<i;n++)
        std::cout << a[n] << "\n";

    return 0;
}

Since my solution got AC, there IS a limit on k... or the tests are too weak.